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mojhsa [17]
3 years ago
11

I need the solution

Mathematics
1 answer:
Readme [11.4K]3 years ago
7 0

Answer:

2c

Step-by-step explanation:

8c^3           2c^2

------------ ÷ -------------

6 (c+d)       3c+3d

Factor the 3 out of the denominator in the last  term

8c^3           2c^2

------------ ÷ -------------

6 (c+d)       3(c+d)

Since this is division, we can use copy dot flip

8c^3          3(c+d)

------------ * -------------

6 (c+d)       2c^2

We can cancel the (c+d) in the denominator on the left and the numerator on the right

8c^3          3

------------ * -------------

6                2c^2

We can cancel c^2 from the numerator on the left (leaving a c) and the denominator on the right

8c             3

------------ * -------------

6                2

24c

-----

12

24/12 = 2  so we are left with

2c

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8 0
4 years ago
Zap’s car rental charges $15.00 an hour to rent a car.Easy car rental charges $8.50 an hour plus a rental fee of $25.50 per rent
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5 0
3 years ago
Read 2 more answers
Questions and answers attached
Black_prince [1.1K]

Answer:

(3)(c) + 43 ≥ 100

Step-by-step explanation:

Given:

Total number of friends = 3 friends

Number of card already have = 43

Total number of card at least want to collect = 100

Find:

Inequality

Computation:

Assume;

Same number of card each friend collect = c

Total number of card at least want to collect ≤ (Total number of friends)(Same number of card each friend collect) + Number of card already have

Total number of card at least want to collect ≤ (3)(c) + 43

100 ≤ (3)(c) + 43

(3)(c) + 43 ≥ 100

3 0
3 years ago
Which of the following expressions represents the least common multiple of 15, 18, and 25?
Virty [35]

Answer:

(2)(3^2)(5^2)

Step-by-step explanation:

we know that

The <u>Least Common Multiple</u> (LCM) of a group of numbers is the smallest number that is a multiple of all the numbers.

we have

15,18 and 25

Decompose the numbers in prime factors

15=(3)(5)

18=(2)(3^2)

25=(5^2)

Multiply common and uncommon numbers with their greatest exponent

so

The LCM is equal to

LCM=(2)(3^2)(5^2)

LCM=450

7 0
3 years ago
verify that the fucntion satisfies the three hypotheses of rolles theorem on the given interval . then find all numbers c that s
Ghella [55]

The roots of the polynomial <span><span>x^3 </span>− 2<span>x^2 </span>− 4x + 2</span> are:

<span><span>x1 </span>= 0.42801</span>

<span><span>x2 </span>= −1.51414</span>

<span><span>x3 </span>= 3.08613</span>


x1 and x2 are in the desired interval [-2, 2]

f'(x) = 3x^2 - 4x - 4

so we have:

3x^2 - 4x - 4 = 0

<span>x = ( 4 +- </span><span>√(16 + 48) </span>)/6

x_1 = -4/6 = -0.66

x_ 2 = 2

According to Rolle's theorem, we have one point in between:

x1 = 0.42801 and x2 = −1.51414

where f'(x) = 0, and that is <span>x_1 = -0.66</span>

so we see that Rolle's theorem holds in our function.

4 0
3 years ago
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