What to do do I subtract the corridnates or add them
1 answer:
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Answer:
Using the transitive property of geometry, we proved that △PQR is an equilateral triangle.
Step-by-step explanation:
The diagram of the given scenario is in the attachment.
Here, PQ is the radius of circle Q
Also, PQ is the radius of circle P
Hence, circle-P and circle-Q have same radii.
Now, PQ=RQ as both are radii of circle Q
And PQ=PR, as both are radii of circle P
Hence as per transitive property, which states that, if any two angles, lines, or shapes are congruent to a third angle, line, or shape respectively, then the first two angles, lines, or shapes are also congruent to the third angle, line, or shape
PR=QR
Now, PQ = QR = PR
Hence, ∆PQR is equilateral.
For more explanation, refer the following link:
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