Answer:
CLASS FREQUENCIES RELATIVE FREQUENCIES
A 60 0.5
B 12 0.1
C 48 0.4
TOTAL 120 1
Step-by-step explanation:
Given that;
the frequencies of there alternatives are;
Frequency A = 60
Frequency B = 12
Frequency C = 48
Total = 60 + 12 + 48 = 120
Now to determine our relative frequency, we divide each frequency by the total sum of the given frequencies;
Relative Frequency A = Frequency A / total = 60 / 120 = 0.5
Relative Frequency B = Frequency B / total = 12 / 120 = 0.1
Relative Frequency C = Frequency C / total = 48 / 120 = 0.4
therefore;
CLASS FREQUENCIES RELATIVE FREQUENCIES
A 60 0.5
B 12 0.1
C 48 0.4
TOTAL 120 1
<u>4</u>
<u></u>
Explanation:
3, 4, 2, 8, 5
<u>arrange in ascending order</u>
2, 3, 4, 5, 8
<u>Identify the integer at the middle</u>
median: 4
I believe it's 12 because 5*16=80. So, then you would subtract 4 from 16 and gat 12.
B it is horizontally stretched by a factor of of 3 and reflected over the y
