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3 years ago

6

What is the factor of

x" alt=" {x}^{4} - x" align="absmiddle" class="latex-formula">
Plz

1 answer:

galina1969 [7]3 years ago

8 0

This is the answer I guess

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Which of the following numbers are considered integers? Please choose all that apply.

Levart [38]

Answer:

0 is answer i think plz give me brainliest

Step-by-step explanation:

Hi if you are satisfied with my answer, don't forget to give brain list.

7 0

3 years ago

What expression is equivalent to ^3 square root of 2y^3 times 7 square root of 18y

Mumz [18]

Answer:

$\sqrt[3]{2y^3} * 7\sqrt{18y} = 21(y^{\frac{3}{2}})(2^{\frac{5}{6}})$

Step-by-step explanation:

The question is poorly formatted.

Given

$\sqrt[3]{2y^3} * 7\sqrt{18y}$

Required

Derive an equivalent expression

$\sqrt[3]{2y^3} * 7\sqrt{18y}$

Express 18 as 9 * 2

$\sqrt[3]{2y^3} * 7\sqrt{9 * 2y}$

Split the expression as follows:

$\sqrt[3]{2y^3} * 7\sqrt{9} * \sqrt{2y}$

Take positive square root of 9

$\sqrt[3]{2y^3} * 7*3 * \sqrt{2y}$

$\sqrt[3]{2y^3} * 21 * \sqrt{2y}$

$21*\sqrt[3]{2y^3} * \sqrt{2y}$

The cube root can be rewritten to give:

$21*\sqrt[3]{2}*\sqrt[3]{y^3} * \sqrt{2y}$

$\sqrt[3]{y^3} = y^{3*\frac{1}{3}} = y$

So, we have:

$21*\sqrt[3]{2} * y * \sqrt{2y}$

Rewrite as:

$21y *\sqrt[3]{2} * \sqrt{2y}$

Split $\sqrt{2y$

$21y *\sqrt[3]{2} * \sqrt{2} * \sqrt{y}$

Collect Like Terms

$21y*\sqrt{y} *\sqrt[3]{2} * \sqrt{2}$

Represent in index form

$21y*y^{\frac{1}{2}} *2^\frac{1}{3} *2^\frac{1}{2}$

Apply law of indices

$21*y^{1+\frac{1}{2}} *2^{\frac{1}{3} +\frac{1}{2} }$

$21*y^{\frac{2+1}{2}} *2^{\frac{2+3}{6}}$

$21*y^{\frac{3}{2}} *2^{\frac{5}{6}}$

$21(y^{\frac{3}{2}})(2^{\frac{5}{6}})$

Hence:

$\sqrt[3]{2y^3} * 7\sqrt{18y} = 21(y^{\frac{3}{2}})(2^{\frac{5}{6}})$

6 0

3 years ago

The bottom of a ladder must be placed 2 1/2 feet from the wall. The ladder is 9 feet long How far above ground is the ladder tou

Gnoma [55]

Answer:

Step-by-step explanation:

$h=\sqrt{9^2-(\frac{5}{2} )^2}\\=\sqrt{81-\frac{25}{4} } \\=\sqrt{\frac{299}{4} } \\=\frac{\sqrt{299} }{2} \\\approx 8.6458\\\approx 8.65 ~ft$

7 0

3 years ago

Read 2 more answers

Pls awnser asap!!!!!!!!!!!!!!!!!!!!!!!!!!!

dexar [7]

Answer:

0.875

Step-by-step explanation:

they're proportional.

7 0

3 years ago

Solve n^4-11n^2+30÷n^4-7n^2+10

Morgarella [4.7K]

Factor the numerator and denominator...

(n^4-5n^2-6n^2+30)/(n^4-2n^2-5n^2+10)

[n^2(n^2-5)-6(n^2-5)]/[n^2(n^2-2)-5(n^2-2)]

[(n^2-5)(n^2-6)]/[(n^2-5)(n^2-2)] notice the (n^2-5)s cancel out

(n^2-6)/(n^2-2)

We could further factor this because each is a difference of squares to:

[(n+√6)(n-√6)]/[(n+√2)(n-√2)

8 0

3 years ago