Question

According to the general equation for conditional probability, if P(A upside down u B)= 5/7 and P(B)=7/8 , what is P(A|B)?

Answer 1

$P(A | B) = \frac{P(A \cap B)}{P(B)}$


$P(A|B) = \frac{5/7}{7/8}$


$P(A|B) = \frac{5}{7} \div \frac{7}{8}$


$P(A|B) = \frac{5}{7}\times\frac{8}{7}$


$P(A|B) = \frac{5*8}{7*7}$


$P(A|B) = \frac{40}{49}$