All categories

3 years ago

PLEASE HELP PLEASE PLEASE

Mathematics

1 answer:

Lera25 [3.4K]3 years ago

7 0

$\lim\limits_{x\to\infty}\dfrac{2}{x}=\left[\dfrac{2}{\infty}\right]=0\\\\\lim\limits_{x\to-\infty}\dfrac{2}{x}=\left[\dfrac{2}{-\infty}\right]=0$

You might be interested in

A new shoe comes in two colors,black or red,and in sizes 5 to 12,including half sizes.If a pair of the shoes is chosen at random

Dima020 [189]

Less then 50% thats foshow

5 0

2 years ago

Write the standard equation of a circle with center (-4 0) and radius 3 brainly

den301095 [7]

(x-4)^2+(y-0)^2=3^2 is the answer

8 0

2 years ago

PLEASE HELP AND SHOW WORK PLEASE.

Vaselesa [24]

Inequalities help us to compare two unequal expressions. There exists no solution to the given set of inequalities.

<h3>What are inequalities?</h3>

Inequalities help us to compare two unequal expressions. Also, it helps us to compare the non-equal expressions so that an equation can be formed. It is mostly denoted by the symbol <, >, ≤, and ≥.

The given Inequalities can be solved as,

5 - x > 7

-x > 7 - 5

-x > 2

x < -2

2x + 3 ≥ 13

2x ≥ 10

x ≥ 5

As per the solution of the two inequalities, the value of x should be less than -2 but at the same time, it should be more than or equal to 5, which is impossible. Thus, there is no solution for the given inequalities.

This can be confirmed by graphing the two inequalities, as shown below. Since there is no area in common between the two inequalities, there exists no solution to the given set of inequalities.

Learn more about Inequality:

brainly.com/question/19491153

#SPJ1

4 0

2 years ago

T-7=19 what is the answer and how do you do it

jeka57 [31]

T=26
you just add 7 to the other side with 19 which gives you the answer

7 0

3 years ago

If each data is increased by a constant K then find it's mean ?? answer fast pleaseeeeeeeeeee

MArishka [77]

Answer:

The mean is also increased by the constant k.

Step-by-step explanation:

Suppose that we have the set of N elements

{x₁, x₂, x₃, ..., xₙ}

The mean of this set is:

M = (x₁ + x₂ + x₃ + ... + xₙ)/N

Now if we increase each element of our set by a constant K, then our new set is:

{ (x₁ + k), (x₂ + k), ..., (xₙ + k)}

The mean of this set is:

M' = ( (x₁ + k) + (x₂ + k) + ... + (xₙ + k))/N

M' = (x₁ + x₂ + ... + xₙ + N*k)/N

We can rewrite this as:

M' = (x₁ + x₂ + ... + xₙ)/N + (k*N)/N

and (x₁ + x₂ + ... + xₙ)/N was the original mean, then:

M' = M + (k*N)/N

M' = M + k

Then if we increase all the elements by a constant k, the mean is also increased by the same constant k.

6 0

3 years ago