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DiKsa [7]
3 years ago
15

Some one cans help me to find the answer about the whole shape and tell me how do you get the answer step by step please I need

help

Mathematics
1 answer:
Naya [18.7K]3 years ago
4 0
First let’s call the square shape A and the rectangle shape B.

To find the area of shape A you do 24 x 24 = 576cm squared

To find the area of shape B you do 40 x 24 = 960cm squared

To find the total area you just add the two areas together
576 + 960 = 1536cm squared
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Solve. –4t ≤ 48 A. t ≥ –12 B. t ≤ –12 C. t ≥ 12 D. t ≤ 12
Oksana_A [137]
-4t \leq 48 \ \ \ : |(-4) \\  \\ t  \geq 12

<em>\\\ Ben</em>
3 0
3 years ago
Let f(x,y,z) = ztan-1(y2) i + z3ln(x2 + 1) j + z k. find the flux of f across the part of the paraboloid x2 + y2 + z = 3 that li
Sophie [7]
Consider the closed region V bounded simultaneously by the paraboloid and plane, jointly denoted S. By the divergence theorem,

\displaystyle\iint_S\mathbf f(x,y,z)\cdot\mathrm dS=\iiint_V\nabla\cdot\mathbf f(x,y,z)\,\mathrm dV

And since we have

\nabla\cdot\mathbf f(x,y,z)=1

the volume integral will be much easier to compute. Converting to cylindrical coordinates, we have

\displaystyle\iiint_V\nabla\cdot\mathbf f(x,y,z)\,\mathrm dV=\iiint_V\mathrm dV
=\displaystyle\int_{\theta=0}^{\theta=2\pi}\int_{r=0}^{r=1}\int_{z=2}^{z=3-r^2}r\,\mathrm dz\,\mathrm dr\,\mathrm d\theta
=\displaystyle2\pi\int_{r=0}^{r=1}r(3-r^2-2)\,\mathrm dr
=\dfrac\pi2

Then the integral over the paraboloid would be the difference of the integral over the total surface and the integral over the disk. Denoting the disk by D, we have

\displaystyle\iint_{S-D}\mathbf f\cdot\mathrm dS=\frac\pi2-\iint_D\mathbf f\cdot\mathrm dS

Parameterize D by

\mathbf s(u,v)=u\cos v\,\mathbf i+u\sin v\,\mathbf j+2\,\mathbf k
\implies\mathbf s_u\times\mathbf s_v=u\,\mathbf k

which would give a unit normal vector of \mathbf k. However, the divergence theorem requires that the closed surface S be oriented with outward-pointing normal vectors, which means we should instead use \mathbf s_v\times\mathbf s_u=-u\,\mathbf k.

Now,

\displaystyle\iint_D\mathbf f\cdot\mathrm dS=\int_{u=0}^{u=1}\int_{v=0}^{v=2\pi}\mathbf f(x(u,v),y(u,v),z(u,v))\cdot(-u\,\mathbf k)\,\mathrm dv\,\mathrm du
=\displaystyle-4\pi\int_{u=0}^{u=1}u\,\mathrm du
=-2\pi

So, the flux over the paraboloid alone is

\displaystyle\iint_{S-D}\mathbf f\cdot\mathrm dS=\frac\pi2-(-2\pi)=\dfrac{5\pi}2
6 0
3 years ago
Aaron is 15 centimeters taller than Peter, and five times Aaron's height exceeds two times Peter's height by 525 centimeters.
Sergio [31]
The answer for this problem would be x equal to 430 cm and y is equal to 325. This is computed by establishing the equations. This first equation based on first statement would be x = 15 + y and the second would be 5x = 3y + 525. Then it is solve as follows:

5x = 3y + 525 
4 0
3 years ago
Read 2 more answers
How do you determine where to place the decimal point in the product?
frez [133]

Let's look at an example:

2.24 x 21.6

2.24\\ 21.6\\ ______

Do normal multiplication and get

48384   This is not correct, until we put the decimals in. To know how to do this, count the number of decimal spaces from the factors. In 2.24, there are 2, because .24. In 21.6 there are 1 because of .6. This mean three places, so 48384 becomes

48.384

~theLocoCoco

7 0
3 years ago
What is the equation of the parabola?
Neporo4naja [7]

Answer:

y = -1/8 x² + 5

Step-by-step explanation:

Parabola opens vertically and vertex (h,k) = (0,5), pass point (4,3)

basic formula: y = a(x - h)² + k

y = a (x-0)² + 5

y = ax² + 5         pass (4,3)

3 = 16a + 5

a = (3-5)/16 = -1/8

equation: y = -1/8 x² + 5

check: pass another point (-4,3)

-1/8 * (-4)² + 5 = -2 + 5 = 3

5 0
3 years ago
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