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Ostrovityanka [42]
3 years ago
9

How do you solve -4x-2y=-24

Mathematics
1 answer:
Mars2501 [29]3 years ago
8 0

Answer:

y = −2x + 12

Step-by-step explanation:

Solve for the first variable in one of the equations, then substitute the result into the other equation.

Please Mark Brainliest!

Hope this helps!

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Solve for a and graph the solution on the number line below.
oksian1 [2.3K]

Solve for x and graph the solution on the number line below.

$$-x-5 \geq 1 \text { or }-x-5 < -8$$

$$-x-5 \geq 1$$

Add 5 to both sides

$$-x-5+5 \geq 1+5$$

Simplify

$$-x \geq 6$$

Multiply both sides by - 1 (reverse the inequality)$(-x)(-1) \leq 6(-1)$

Simplify

$$x \leq-6$$

$-x-5 < -8$

Add 5 to both sides

$-x-5+5 < -8+5$

Simplify

$-x < -3$

Multiply both sides by $-1$ (reversing the inequality)

$(-x)(-1) > (-3)(-1)$

Simplify

$x > 3$

The idea of inequality, which is the state of not being equal, especially in terms of status, rights, and opportunities, is at the core of social justice theories. However, because it frequently has diverse meanings to different individuals, it is prone to misunderstanding in public discourse. However, certain distinctions are universal.

In mathematics, inequalities specify the connection between two non-equal numbers. Equal does not imply inequality. Typically, we use the "not equal sign (≠)" to indicate that two values are not equal. But several inequalities are utilized to compare the numbers, whether it is less than or higher than.

Learn more about inequalities brainly.com/question/20383699

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7 0
1 year ago
The time college students spend on the internet follows a Normal distribution. At Johnson University, the mean time is 5 hrs wit
netineya [11]

Answer:

The probability that the average time 100 random students on campus will spend more than 5 hours on the internet is 0.5

Step-by-step explanation:

We are given that . At Johnson University, the mean time is 5 hrs with a standard deviation of 1.2 hrs.

Mean = \mu = 5 hours

Standard deviation = \sigma = 1.2 hours

We are supposed to find the probability that the average time 100 random students on campus will spend more than 5 hours on the internet i.e. P(X>5)

Z=\frac{x-\mu}{\sigma}

Z=\frac{5-5}{1.2}

Z=0

P(X>5)=1-P(X<5)=1-P(Z<0)=1-0.5=0.5

Hence the probability that the average time 100 random students on campus will spend more than 5 hours on the internet is 0.5

7 0
3 years ago
Given that f(x) = x2 − 3x + 3 and g(x) = the quantity of x minus one, over four, solve for f(g(x)) when x = 5.
Katena32 [7]

g(x) = the quantity of x minus one, over four

g(x) = (x-1)/4

g(5) = (5-1)/4

g(5) = 4/4

g(5) = 1


f(x) = x2 − 3x + 3

f(g(5)) =1^2 − 3(1) + 3

f(g(5)) = 1 - 3 + 3

f(g(5)) = 1


7 0
4 years ago
It costs four dollars to enter the fair each ride costs $2.50 you have $21.50 how many rides can you go on?
laiz [17]
7 rides because
you got $21.50
You subtract $4.00 to enter in the fair
Tha equals $17.5
You divide that 2.50
that equals 7

Hope i had helped
6 0
3 years ago
What is 2 eight over 2 cubed
olga nikolaevna [1]
32

Hope it’s right
Best luck with your studying
6 0
3 years ago
Read 2 more answers
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