Question

The time college students spend on the internet follows a Normal distribution. At Johnson University, the mean time is 5 hrs with a standard deviation of 1.2 hrs. What is the probability that the average time 100 random students on campus will spend more than 5 hours on the internet

Answer 1

Answer:

The probability that the average time 100 random students on campus will spend more than 5 hours on the internet is 0.5

Step-by-step explanation:

We are given that . At Johnson University, the mean time is 5 hrs with a standard deviation of 1.2 hrs.

Mean = $\mu = 5 hours$

Standard deviation = $\sigma = 1.2 hours$

We are supposed to find the probability that the average time 100 random students on campus will spend more than 5 hours on the internet i.e. P(X>5)

$Z=\frac{x-\mu}{\sigma}$

$Z=\frac{5-5}{1.2}$

Z=0

P(X>5)=1-P(X<5)=1-P(Z<0)=1-0.5=0.5

Hence the probability that the average time 100 random students on campus will spend more than 5 hours on the internet is 0.5