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EastWind [94]
4 years ago
15

In the 2000-2001 season, Shaquille O'Neal made 813 field goals out of 1422 attempts. What was his ratio of successful field goal

s to failed attempts? Write your answer as botha fraction in the simplest form and a decimal rounded to the nearest thousandth.
Mathematics
1 answer:
iragen [17]4 years ago
7 0
Answer=1.335 or 1 67/200

813 field goals
1422 attempts

1422-813=609 fails

813/609=1.335 successes per fail

1.335= 1 335/1000= 1 67/200
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Which of the following illustrates the truth value of the given statements?
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Answer:oft-t

Step-by-step explanation:

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3 years ago
A line with a negative slope and a negative
Alina [70]

Answer:

<h2>First quadrant will the line not pass.</h2>

Step-by-step explanation:

The given line has a negative slope. It means with increasing value of x, y will be decreasing. It has a negative y-intercept that is at x = 0, y is less than 0.

If the value of x will be greater than 0, the value of y will be going downwards continuously.

If x > 0, y < 0, as the line has a negative y-intercept.

A point in first quadrant means x > 0 as well as y > 0.

Hence, the line cannot pass through the first quadrant.

7 0
4 years ago
Solve: 2/3x - 3/4 = 5 + 5/6x
Slav-nsk [51]

Answer:

\large\boxed{x=-\dfrac{69}{2}\to x=-34\dfrac{1}{2}\to x=-34.5}

Step-by-step explanation:

\dfrac{2}{3}x-\dfrac{3}{4}=5+\dfrac{5}{6}x\qquad\text{multiply both sides by LCD = 12}\\\\12\!\!\!\!\!\diagup^4\cdot\dfrac{2}{3\!\!\!\!\diagup_1}x-12\!\!\!\!\!\diagup^3\cdot\dfrac{3}{4\!\!\!\diagup_1}=(12)(5)+12\!\!\!\!\!\diagup^2\cdot\dfrac{5}{6\!\!\!\diagup_1}x\\\\(4)(2x)-(3)(3)=60+(2)(5x)\\\\8x-9=60+10x\qquad\text{add 9 to both sides}\\\\8x-9+9=60+9+10x\\\\8x=69+10x\qquad\text{subtract}\ 10x\ \text{from both sides}\\\\8x-10x=69+10x-10x\\\\-2x=69\qquad\text{divide both sides by (-2)}\\\\x=-\dfrac{69}{2}

7 0
3 years ago
Need help fast plz for my pre calc exam
bezimeni [28]

Answer:

<em>h = 8.54 units</em>

Step-by-step explanation:

<u>The Law of Cosines </u>

It relates the length of the sides of a triangle with one of its internal angles.

Let a,b, and c be the length of the sides of a given triangle, and x the included angle between sides a and b, then the following relation applies:

c^2=a^2+b^2-2ab\cos x

Since we know the values of all three side lengths, we solve the equation for x:

\displaystyle \cos x=\frac{a^2+b^2-c^2}{2ab}

For the triangle ABC in the image, a=10, b=15, c=13, thus:

\displaystyle \cos A=\frac{10^2+15^2-13^2}{2*10*15}

\displaystyle \cos A=\frac{156}{300}

\displaystyle \cos A=0.52

Thus, A = 58.67°

For the right triangle of height h and hypotenuse 10, we use the sine ratio:

\displaystyle \sin 58.67^\circ=\frac{h}{10}

Solving for h:

h = 10\sin 58.67^\circ

h = 8.54 units

6 0
3 years ago
X² + y² = 36<br> State the domain and range of the relation
meriva

Answer:

Domain: from -6 to 6, inclusive

Range: from -6 to 6, inclusive

Step-by-step explanation:

It's a circle centred at origin with radius 6

4 0
3 years ago
Read 2 more answers
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