The intersection of the two sets is the list of members that appear in both sets. That is {3}.
Your statement is FALSE.
If you notice, the container is really just two circles, with a diameter of 4 each, and a square with sides of 10.5.
now, if we just get the area of each circle, keeping in mind their radius is half of the diameter, namely r = 2, and get the area of the 10.5x10.5 square, sum them up, that'd be the surface area of the container.
Answer:
1
Step-by-step explanation:
JK and KN is perpendicular.
Thus no planes contained them except 1
Which is a rectangle.
I hope this helps you :)