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3 years ago

How do you write 2916 divided by 9 in the Associative Property

1 answer:

7 0

You can only multiply and add with associative property. are you talking about distributive property or identity property

You might be interested in

Lim x--> 0 (e^x(sinx)(tax))/x^2

Tom [10]

Make use of the known limit,

$\displaystyle\lim_{x\to0}\frac{\sin x}x=1$

We have

$\displaystyle\lim_{x\to0}\frac{e^x\sin x\tan x}{x^2}=\left(\lim_{x\to0}\frac{e^x}{\cos x}\right)\left(\lim_{x\to0}\frac{\sin^2x}{x^2}\right)$

since $\tan x=\dfrac{\sin x}{\cos x}$ , and the limit of a product is the same as the product of limits.

$\dfrac{e^x}{\cos x}$ is continuous at $x=0$ , and $\dfrac{e^0}{\cos 0}=1$ . The remaining limit is also 1, since

$\displaystyle\lim_{x\to0}\frac{\sin^2x}{x^2}=\left(\lim_{x\to0}\frac{\sin x}x\right)^2=1^2=1$

so the overall limit is 1.

4 0

3 years ago

F is the midpoint of EG If EF = x + 2 and FG = 2x - 6, find<br> FG

mezya [45]

Answer:

FG = 10

Step-by-step explanation:

EF = x + 2 ; FG = 2x - 6

F is the mid-point of EG. So, EF = FG

$= > x + 2 = 2x - 6$

$= > 2x - x = 6 + 2$

$= > x = 8$

FG = 2×8 - 6 = 10

8 0

3 years ago

What’s the volume of the cylinder

FrozenT [24]

Answer:

188.496 mm^3 (or 188.495559 mm^3 if you want to be specific)

Step-by-step explanation:

The radius would be the distance from the middle of the circle on top, we are given that the diameter of the circle is 4mm, the radius is half of that so you would get 2 as the radius (or R). H is the height of the cylinder which is 15 mm, so plugging it in (pi * (2^2) * 15) would get you 188.496 mm^3 (rounded of course).

3 0

3 years ago

manuel deposits $10000 for 12 yr in an account paying 4% compounded annually.He then puts this total amount on deposit in anothe

Naddik [55]

$\bf ~~~~~~ \textit{Compound Interest Earned Amount}
\\\\
A=P\left(1+\frac{r}{n}\right)^{nt}
\quad 
\begin{cases}
A=\textit{accumulated amount}\\
P=\textit{original amount deposited}\to &\$10000\\
r=rate\to 4\%\to \frac{4}{100}\to &0.04\\
n=
\begin{array}{llll}
\textit{times it compounds per year}\\
\textit{annually, thus once}
\end{array}\to &1\\
t=years\to &12
\end{cases}
\\\\\\
A=10000\left(1+\frac{0.04}{1}\right)^{1\cdot 12}\implies A=1000(1.04)^{12}\\\\\\ A\approx 16010.32$

he then turns around and grabs that money and sticks it for another 9 years,

$\bf ~~~~~~ \textit{Compound Interest Earned Amount}
\\\\
A=P\left(1+\frac{r}{n}\right)^{nt}
~~
\begin{cases}
A=\textit{accumulated amount}\\
P=\textit{original amount deposited}\to &\$16010.32\\
r=rate\to 5\%\to \frac{5}{100}\to &0.05\\
n=
\begin{array}{llll}
\textit{times it compounds per year}\\
\textit{semi-annually, thus twice}
\end{array}\to &2\\
t=years\to &9
\end{cases}
\\\\\\
A=16010.32\left(1+\frac{0.05}{2}\right)^{2\cdot 9}\implies A=16010.32(1.025)^{18}
\\\\\\
A\approx 24970.64$

add both amounts, and that's how much is for the whole 21 years.

6 0

3 years ago

Someone help pls and thanks

Amiraneli [1.4K]

C I am soooo sorry if I’m wrong

4 0

2 years ago