Answer:
352 students
Step-by-step explanation:
Given
See attachment for table
![n = 400](https://tex.z-dn.net/?f=n%20%3D%20400)
Required
Attendance of students in this year's show
First, we calculate the mean of the table
![Mean= \frac{\sum x}{n}](https://tex.z-dn.net/?f=Mean%3D%20%5Cfrac%7B%5Csum%20x%7D%7Bn%7D)
So, we have:
![Mean= \frac{85\% + 91\% + 92\% + 87\% +84\% + 89\%}{6}](https://tex.z-dn.net/?f=Mean%3D%20%5Cfrac%7B85%5C%25%20%2B%2091%5C%25%20%2B%2092%5C%25%20%2B%2087%5C%25%20%2B84%5C%25%20%2B%2089%5C%25%7D%7B6%7D)
![Mean= \frac{528\%}{6}](https://tex.z-dn.net/?f=Mean%3D%20%5Cfrac%7B528%5C%25%7D%7B6%7D)
![Mean= 88\%}](https://tex.z-dn.net/?f=Mean%3D%2088%5C%25%7D)
Multiply the mean by the total students
![Expected = Mean * n](https://tex.z-dn.net/?f=Expected%20%3D%20Mean%20%2A%20n)
![Expected = 88\% * 400](https://tex.z-dn.net/?f=Expected%20%3D%2088%5C%25%20%2A%20400)
![Expected = 352](https://tex.z-dn.net/?f=Expected%20%3D%20352)
9514 1404 393
Answer:
$20.01
Step-by-step explanation:
In 2004–2012, the interest rate is 0.002%. In 2013, it is 0.004%. In 2014–2021, the interest rate is 0.002%. That is, in the 18 years between 2004 and 2021 (inclusive), the interest rate is 0.002% for 17 of them. The effective account multiplier is ...
(1.00002^17)(1.00004^1) = 1.00038006801
Then the account balance is ...
$20 × 1.00038006801 ≈ $20.01
_____
<em>Additional comment</em>
The annual interest earned on $20.00 is $0.0004. If the account balance is rounded to the nearest cent annually, at the end of the 18 years, the balance will still be $20.00. Not enough interest is earned in one year to increase the balance above $20. At the end of the 18 years, the amount of interest earned is 0.76¢ (a fraction of a penny) <em>only if there is no rounding in intervening years</em>.
Answer:
(-11,-8)
Step-by-step explanation:
40 - 4f = -70 - 10f
6f = -110
f = -55/3
Answer:
The final position is 5 feet below the back of the truck
Step-by-step explanation:
* Lets explain how to solve the problem
- A crane lifts a pallet of concrete blocks 8 feet from the back of
a truck
- The crane lowers the pallet 13 feet after the truck drives away
- Assume that the zero level of the position of the ballet of concrete
blocks is the back of the truck
∵ The crane lifts the pallet of concrete blocks 8 feet from the back
of the truck
- That means it take the pallet from zero to 8
∴ The height of the pallet of concrete blocks is 8 feet over
the starting position
∵ The crane lowers the pallet of concrete blocks 13 feet
- That means the crane lower the pallet from the height 8 and
lift it down 13 feet, so we must to take out from the 8 feet the
13 feet to find the final position of the pallet of concrete blocks
∴ The pallet position is ⇒ 8 - 13 = -5
∴ The position of the pallet of concrete blocks is 5 feet below the
starting position which is the back of the truck
* The final position is 5 feet below the back of the truck