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KiRa [710]
3 years ago
11

The sum of 4 consecutive even integers is -12. find the largest integer.

Mathematics
1 answer:
Ipatiy [6.2K]3 years ago
6 0

Answer:

The largest even integer is 0

Step-by-step explanation:

Given as :

The sum of four consecutive even number = - 12

Let The first even number = 2 x

The second even number = (2 x + 2)

The third even number = (2 x + 4)

The fourth even number = (2 x + 6)

<u>According to question</u>

sum of four consecutive even number = - 12

Or, 2 x + (2 x + 2) + (2 x + 4) + (2 x + 6) = - 12

Or, (2 x + 2 x + 2 x + 2 x) + (2 + 4 + 6) = - 12

Or, 8 x + 12 = - 12

Or, 8 x = - 12 - 12

Or, 8 x = - 24

∴  x = \frac{- 24}{8}

i.e  x = - 3

now, putting the value of x

The first even number = 2 × - 3 = - 6

The second even number = (2 × - 3 + 2) = - 6 + 2 = - 4

The third even number = (2 × - 3 + 4) = - 6 + 4 = - 2

The fourth even number = (2 × - 3 + 6) = - 6 + 6 = 0

So, The largest even integer = 0

Hence, The largest even integer is 0  Answer

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3 years ago
A 15-ft ladder leans against a wall. The lower end of the ladder is being pulled away from the wall at the rate of 1.5 ft/sec. L
Aleks [24]

Answer:

The top of the ladder is sliding down at a rate of 2 feet per second.

Step-by-step explanation:

Refer the image for the diagram. Consider \Delta ABC as right angle triangle. Values of length of one side and hypotenuse is given. Value of another side is not known. So applying Pythagoras theorem,

\left ( AB \right )^{2}+\left ( BC \right )^{2}=\left ( AC \right )^{2}

From the given data, L=15\:ft=AC, y=9\:ft=AB and x=BC

Substituting the values,  

\therefore \left ( 9 \right )^{2}+\left ( x \right )^{2}=\left ( 15 \right )^{2}

\therefore 81+x^{2}=225

\therefore x^{2}=225-81

\therefore x^{2}=144

\therefore \sqrt{x^{2}}=\sqrt{144}

\therefore x=\pm 12

Since length can never be negative, so x= 12.

Now to calculate \dfrac{dy}{dt} again consider following equation,  

\left ( y \right )^{2}+\left ( x \right )^{2}=\left ( l \right )^{2}

Differentiate both sides of the equation with respect to t,  

\dfrac{d}{dt}\left(y^2+x^2\right)=\dfrac{d}{dt}\left(l^2\right)

Applying sum rule of derivative,

\dfrac{d}{dt}\left(y^2\right)+\dfrac{d}{dt}\left(x^2\right)=\dfrac{d}{dt}\left(l^2\right)

\dfrac{d}{dt}\left(y^2\right)+\dfrac{d}{dt}\left(x^2\right)=\dfrac{d}{dt}\left(225\right)

Applying power rule of derivative,  

2y\dfrac{dy}{dt}+2x\dfrac{dx}{dt}=0

Simplifying,  

y\dfrac{dy}{dt}+x\dfrac{dx}{dt}=0

Substituting the values,  

9\dfrac{dy}{dt}+12\times1.5=0

9\dfrac{dy}{dt}+18=0

Subtracting both sides by 18,

9\dfrac{dy}{dt}=-18

Dividing both sides by 9,

\dfrac{dy}{dt}= - 2

Here, negative indicates that the ladder is sliding in downward direction.  

\therefore \dfrac{dy}{dt}= 2\:\dfrac{ft}{sec}

7 0
3 years ago
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