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3 years ago

What goes outside during division with fractions? The numerator, or the denominator?

Mathematics

1 answer:

Ymorist [56]3 years ago

6 0

Answer:

Denominator

Step-by-step explanation:

Think of it this way - numerator/denominator = nana/dog

Nana goes inside to the bathroom, but the dog goes outside to do its thing

If it was the other way around, it wouldn't be very pleasant.

LOL

Anyway, I hope this was helpful

Mark as Brainliest if it was

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HELP!!!!!!!!!!

Vadim26 [7]

Answer:

A)Points are A ,B,C,D,G,E

B) other names are AC, CA, ABC

C)the Rays are DE, DG

D) M refers to the plane in which these points and Rays,lines are mentioned

E) < GDE < EDG are other names for angle 1

Explanation:

A line is one which has arrow heads on both ends and extends infinitely .

A ray has arrow Head at one end.

An angle is formed by the joining of two rays or lines.

Points are specific locations on a line or ray .

A plane has two dimensions length and breadth which has a line etc drawn on it

7 0

2 years ago

I need help please.

Fed [463]

Answer:

$3420

Step-by-step explanation:

multiply 95 by 36

4 0

2 years ago

3.14(a2 + ab) when a = 4 and b = 2.

Debora [2.8K]

Just replace a with 4 and b with 2 and your equation looks like
3.14 (4×2+4×2)
solve within the parenthesis first
3.14 (8+8)
3.14 (16) =50.24

5 0

3 years ago

If an equation has one solution, what will the variable terms be<br>a. the same<br>b. different

Alik [6]

Answer:

If an equation has one solution, what will the variable terms be

b. different

8 0

2 years ago

Triangle ABC is an isosceles triangle in which side

Shkiper50 [21]

Answer:

Option B.

Step-by-step explanation:

Consider the below figure attached with this question.

It is given that triangle ABC is an isosceles triangle.

From the below figure it is clear that the vertices of triangle are A(-2,-4), B(2,-1) and C(3,-4).

Distance formula:

$d=\sqrt{(x_2-x_1)^2+(y_2-y_1)^2}$

Using this formula, we get

$AB=\sqrt{(2-(-2))^2+(-1-(-4))^2}=\sqrt{16+9}=5$

$BC=\sqrt{(3-2)^2+(-4-(-1))^2}=\sqrt{1+9}=\sqrt{10}$

$AC=\sqrt{(3-(-2))^2+(-4-(-4))^2}=\sqrt{25}=5$

Now,

Perimeter of triangle ABC = AB + BC + AC

$=5+\sqrt{10}+5$

$=10+\sqrt{10}$

So, perimeter of triangle ABC is $10+\sqrt{10}$ units.

Therefore, the correct option is B.

4 0

2 years ago

Read 2 more answers