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quester [9]
2 years ago
14

Which of the following shapes could be formed by taking a longitudinal section perpendicular to the base of a rectangular prism?

Mathematics
1 answer:
balu736 [363]2 years ago
3 0

The longitudinal section perpendicular to the base of a rectangular prism is a rectangle.

<h3>What is a three dimensional shape?</h3>

A three dimensional shape is a shape that has length, width and height. Examples of three dimensional shapes are<em> cone, cylinder, prism and pyramid.</em>

A two dimensional shape is a shape that have both length and width. Examples of two dimensional shape are <em>circle, rectangle, square</em>.

A rectangular prism is a three-dimensional shape, having six faces, where all the faces are rectangles.

The longitudinal section perpendicular to the base of a rectangular prism is a rectangle.

Find out more on three dimensional shape at: brainly.com/question/6636176

#SPJ1

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Step-by-step explanation:

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An object that weighs 24 pounds on Mercury weighs approximately 80 pounds on Earth. A rock weighs 240 pounds on Mercury. What is
AnnyKZ [126]

Answer:

800 pounds.

Step-by-step explanation:

We have been given that an object that weighs 24 pounds on Mercury weighs approximately 80 pounds on Earth. A rock weighs 240 pounds on Mercury. We are asked to find the weight of rock on Earth.

We will use proportions to solve our given problem as proportions state that the ratio between two proportional quantities is equal.

\frac{\text{Weight on Earth}}{\text{Weight on Mercury}}=\frac{80}{24}

Upon substituting our given value, we will get:

\frac{\text{Weight on Earth}}{240}=\frac{80}{24}

\frac{\text{Weight on Earth}}{240}\cdot 240=\frac{80}{24}\cdot 240

\text{Weight on Earth}}=\frac{80}{1}\cdot 10

\text{Weight on Earth}=800

Therefore, the weight of rock on Earth would be approximately 800 pounds.

4 0
3 years ago
A body moves s metres in a time t seconds so that s = t3 – 3t2 + 8. Find:
Lady bird [3.3K]

Using derivatives, it is found that:

i) v(t) = 3t^2 - 6t

ii) 9 m/s.

iii) a(t) = 6t - 6

iv) 6 m/s².

v) 1 second.

<h3>What is the role of derivatives in the relation between acceleration, velocity and position?</h3>
  • The velocity is the derivative of the position.
  • The acceleration is the derivative of the velocity.

In this problem, the position is:

s(t) = t^3 - 3t^2 + 8

item i:

Velocity is the <u>derivative of the position</u>, hence:

v(t) = 3t^2 - 6t

Item ii:

v(3) = 3(3)^2 - 6(3) = 27 - 18 = 9

The speed is of 9 m/s.

Item iii:

Derivative of the velocity, hence:

a(t) = 6t - 6

Item iv:

a(2) = 6(2) - 6 = 6

The acceleration is of 6 m/s².

Item v:

t for which a(t) = 0, hence:

6t - 6 = 0

6t = 6

t = \frac{6}{6}

t = 1

Hence 1 second.

You can learn more about derivatives at brainly.com/question/14800626

7 0
2 years ago
NEED HELP ASAPInstructions: Find the length of the missing sides. Round your answers to the
Pie

Answer:

x = 9.4

y = 17.7

Step-by-step explanation:

Given: The figure

Required: Find x and y

The relationship between length x, length 15 and angle 32 is as follows:

tan \theta = \frac{opp}{adj}

So, we have:

tan\ 32= \frac{x}{15}

Cross multiply:

x =15*tan\ 32

x = 15 * 0.6248693519

x = 9.3730402785

x = 9.4 --- approximated

Similarly:

The relationship between length y, length 15 and angle 32 is as follows:

cos \theta = \frac{adj}{hyp}

So, we have:

cos\ 32= \frac{15}{y}

Cross Multiply:

y * cos\ 32= 15

Solve for y

y = \frac{15}{cos\ 32}

y = \frac{15}{0.84804809615}

y = 17.6876760506

y = 17.7 --- approximated

8 0
3 years ago
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