To prove that jill is wrong we just need an example of this;
2*3*5*7*11*13 = 30030 (this is the smallest number with 6 different prime numbers)
5953*5981*5987 = 2.13x10^11 (which is obviously a much bigger number)
this is enough to prove that jill is wrong
Firstly, seeing that the sequence is based on odd numbers I would say that this is the formula (which will allow you to know whatever term):
nth term = 2n-1
Hope this helps!
Log₄(y+2) = 3, transform it into exponent form:
(y+2) = 4³
y+2 = 64
y= 62
