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satela [25.4K]
4 years ago
14

5 ejemplos de punto de ebullicion

Biology
1 answer:
mamaluj [8]4 years ago
3 0
<span>Sustancia      Punto de fusión       Punto de ebullición

</span>Nitrógeno      -210                         -196
Oxígeno        -218                         -183
Agua             0                             100
Alcohol         -114,4                       87,4
Mercurio        -38,9                        <span>357
</span>Glicerina        -40                           290
Aluminio         660                          2060
Cobre             1083                        2595
Hierro             1539                        2740
Oro                 1064                       2856
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Answer:

1 oz = 29.574 ml

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Explanation:

Hope This Helps

3 0
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Help me please I am so confused
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Meiosis and fertilization are important for the survival of many species because these two processes result in —
lidiya [134]

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8 0
2 years ago
In colorectal cancer, some tumor suppressor genes are inactive. This is an important factor resulting in uncontrolled cell divis
tresset_1 [31]

Answer/Explanation:

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To check to see if there is a mutation, you could extract the DNA from the cancer cells and then perform PCR to amplify the gene of interest. You could then perform sanger sequencing and compare the sequence to the normal gene to see if a mutation is present. To test the effect of the mutation, you would want to see if an active protein has been formed.

To see if a normal sized protein has been formed, you could perform a western blot, comparing the protein band to the WT protein band. If the protein is absent or much smaller, it is likely not a functional protein.

(2) epigenetic silencing at the promoter of the gene, resulting in reduced transcription.

To check for changes in the epigenetic landscape of the promoter, you could perform chromatin immunoprecipitation by extracting the chromatin from the tumour cells and using antibodies for different chromatin marks to see what has changed between the normal cells and the tumor cells. E.g. H3K9me3, H3K27me3. You would perform a pull down with the antibody of interest and then PCR for your promoter to specifically look at changes at that gene compared to normal cells. To test DNA methylation, you could perform bisulfite sequencing.

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3 0
3 years ago
Captive-bred trout reduce the fitness of wild populations, Relative fitness Wild Captive Captive Wild Wild Captive What statemen
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Answer:

A) The gene flow between hatchery-reared and wild populations is leading to a decline in fitness of wild populations.

Explanation:

<u>we have relative fitness at its greatest in trouts whose parents are wild x wild. crossing the wild with hatchery reared causes a decrease in the fitness of the troutgene flow is the exchange of genes between two different breeds. the wild is a greatly diverse breed and it is highly adaptive. while the hatchery reared is less adaptive.when these two breed less fit alleles will then be transferred to the wild</u>

therefore option a answers the question

8 0
3 years ago
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