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RUDIKE [14]
3 years ago
12

The following table shows the boiling points (in °F) of some common liquids and gases at atmospheric pressure. Substance Boiling

Point (°F) Ammonia -28.1 Carbon Dioxide -70.6 Ether 95 Propane -45 What is the temperature difference of the boiling points of propane and carbon dioxide?
Mathematics
2 answers:
Amanda [17]3 years ago
7 0

it would be by -25.6 degrees Fahrenheit

hoa [83]3 years ago
4 0
It would be -25.6 Fahrenheit for your answer
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Bess [88]

well, the assumption is that is a rectangle, namely it has two equal pairs, so we can just find the length of one of the pairs to get the dimensions.

hmmmm let's say let's get the length of the segment at (-1,-3), (1,3) for its length

and

the length of the segment at (-1, -3), (-4, -2) for its width

\bf ~~~~~~~~~~~~\textit{distance between 2 points} \\\\ (\stackrel{x_1}{-1}~,~\stackrel{y_1}{-3})\qquad (\stackrel{x_2}{1}~,~\stackrel{y_2}{3})\qquad \qquad d = \sqrt{( x_2- x_1)^2 + ( y_2- y_1)^2} \\\\\\ \stackrel{length}{L}=\sqrt{[1-(-1)]^2+[3-(-3)]^2}\implies L=\sqrt{(1+1)^2+(3+3)^2} \\\\\\ L=\sqrt{4+36}\implies L=\sqrt{40} \\\\[-0.35em] ~\dotfill

\bf (\stackrel{x_1}{-1}~,~\stackrel{y_1}{-3})\qquad (\stackrel{x_2}{-4}~,~\stackrel{y_2}{-2})\qquad \qquad d = \sqrt{( x_2- x_1)^2 + ( y_2- y_1)^2} \\\\\\ \stackrel{width}{w}=\sqrt{[-4-(-1)]^2+[-2-(-3)]^2}\implies w=\sqrt{(-4+1)^2+(-2+3)^2} \\\\\\ w=\sqrt{9+1}\implies w=\sqrt{10} \\\\[-0.35em] ~\dotfill\\\\ \stackrel{\textit{area of the rectangle}}{A=Lw}\implies \sqrt{40}\cdot \sqrt{10}\implies \sqrt{400}\implies \boxed{20}

7 0
2 years ago
Can someone please help me ​
muminat

Answer:

4) x >= 11

vuvjbnknlnlnononinknin

3 0
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Sara’s hair was 25 inches long. Three years later it was 43 inches long. What was the percent increase rounded to the nearest hu
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Answer:

Increase Percentage =

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Percentage increase in hairlength = 72%

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Answer:

7√(x) = 14

Step-by-step explanation:

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amm1812

Answer:

A

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The blue graph, g(x), is shifted down 8 units.

So the answer is f(x)-8 which is A

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