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Anna71 [15]
3 years ago
5

A woman bought a necklace for $300 and then sold it for $600. She bought it back for $700 and sold it again for $900. How much d

id she gain or lose on these transactions?
Mathematics
2 answers:
Firlakuza [10]3 years ago
8 0

By buying the necklace, she lost $300.

This means she has -300 dollars.

Then, she gained $600 for selling the necklace. Add 600.

-300 + 600 = 300

She now has $300 again.

Next, she buys it for $700. Subtract 700.

300 - 700 = -400

She has negative $400.

Finally, she sells it for $900. Add 900.

-400 + 900 = 500

She has $500 at the end.

Answer:

She gained $500 from the transactions.

laila [671]3 years ago
4 0

Answer: Lost $500

Step-by-step explanation:

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Someone please help, anyone will be awarded brainly
Mnenie [13.5K]

Answer:

THE ANSER IS C.

Step-by-step explanation:

3 0
3 years ago
Read 2 more answers
A.Find the total and area of the compound figures
goldfiish [28.3K]

Answer:

(a) The total area of compound figure is 284.52ft^2.

(b) The total perimeter of compound figure is 68.84 ft.

Step-by-step explanation:

Perimeter: The total distance covered by the figure.

Area: It is defined as the space occupied by the figure.

Given:

Length of rectangular figure = 19 ft

Breadth of rectangular figure = 12 ft

Radius of circle, r = \frac{12ft}{2} = 6 ft

Part (a):

Now calculating the total area of the compound figure.

\text{Total area}=\text{Area of rectangular figure}+\frac{1}{2}\times \text{Area of circle}\\\\\text{Total area}=\text{Length}\times \text{Breadth}+\frac{1}{2}\times \pi r^2

Now putting all the given values in this formula, we get:

\text{Total area}=(19ft\times 12ft)+\frac{1}{2}\times 3.14\times (6ft)^2\\\\\text{Total area}=284.52ft^2

Part (b):

Now calculating the total perimeter of the compound figure.

\text{Total perimeter}=2\times \text{Length}+Breadth+(\frac{1}{2}\times \text{Circumference})\\\\\text{Total perimeter}=2\times \text{Length}+Breadth+(\frac{1}{2}\times 2\times \pi \times r)

Now putting all the given values in this formula, we get:

\text{Total perimeter}=2\times \text{Length}+Breadth+(\frac{1}{2}\times 2\times \pi \times r)\\\\\text{Total perimeter}=2\times 19ft+12ft+(\frac{1}{2}\times 2\times 3.14 \times 6ft)\\\\\text{Total perimeter}=68.84ft

8 0
3 years ago
Matthew has $25 he goes to the movie and spent eight dollars on a movie ticket then four dollars on popcorn do you want to frien
Virty [35]

Answer: $23

Step-by-step explanation:

1) 25-8=17

2) 17-4= 13

3) 13+10= 23

Matthew has $23 now

8 0
4 years ago
What is the answer to this solution. -7r−4≥ 4r+2
tia_tia [17]

Answer:

The solution is:

-7r-4\ge \:\:4r+2\quad \::\quad \:\begin{bmatrix}\mathrm{Solution:}\:&\:r\le \:\:-\frac{6}{11}\:\\ \:\:\mathrm{Decimal:}&\:r\le \:\:-0.54545\dots \:\\ \:\:\mathrm{Interval\:Notation:}&\:(-\infty \:\:,\:-\frac{6}{11}]\end{bmatrix}

Please check the attached line graph below.

Step-by-step explanation:

Given the expression

-7r-4\ge \:4r+2

Add 4 to both sides

-7r-4+4\ge \:4r+2+4

Simplify

-7r\ge \:4r+6

Subtract 4r from both sides

-7r-4r\ge \:4r+6-4r

Simplify

-11r\ge \:6

Multiply both sides by -1 (reverses the inequality)

\left(-11r\right)\left(-1\right)\le \:6\left(-1\right)

Simplify

11r\le \:-6

Divide both sides by 11

\frac{11r}{11}\le \frac{-6}{11}

Simplify

r\le \:-\frac{6}{11}

Therefore, the solution is:

-7r-4\ge \:\:4r+2\quad \::\quad \:\begin{bmatrix}\mathrm{Solution:}\:&\:r\le \:\:-\frac{6}{11}\:\\ \:\:\mathrm{Decimal:}&\:r\le \:\:-0.54545\dots \:\\ \:\:\mathrm{Interval\:Notation:}&\:(-\infty \:\:,\:-\frac{6}{11}]\end{bmatrix}

Please check the attached line graph below.

7 0
3 years ago
Write the first five terms of the sequence in which the nth term is a_n=(n+1)!/n+1.
VikaD [51]

Answer:a) 1,2,6,24,120

Step-by-step explanation:

The formula for the nth term of the sequence is expressed as

n=(n+1)!/n+1

For the first term, n = 1. Therefore,

(1+1)!/(1+1) = 2!/2 = (2×1)/2 = 1

For the second tern, n = 2. Therefore,

(2+1)!/2+1 = 3! /3 = (3×2×1)/3 = 6/3 = 2

For the third term, n = 3, therefore

(3+1)!/3+1 = 4!/4 =(4×3×2×1)/4 = 6

For the fourth term, n = 4. Therefore

(4+1)!/4+1 = 5!/5 = (5×4×3×2×1)/5 = 24

For the fifth term, n = 5. Therefore

(5+1)!/5+1 = 6!/6 = 6× 5×4×3×2×1)/6 = 120

4 0
3 years ago
Read 2 more answers
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