Answer: 6/8, 12/16, 15/20, 18/24, are all equal
Step-by-step explanation:
Answer: Lattice parameter, a = (4R)/(√3)
Step-by-step explanation:
The typical arrangement of atoms in a unit cell of BCC is shown in the first attachment.
The second attachment shows how to obtain the value of the diagonal of the base of the unit cell.
If the diagonal of the base of the unit cell = x
(a^2) + (a^2) = (x^2)
x = a(√2)
Then, diagonal across the unit cell (a cube) makes a right angled triangle with one side of the unit cell & the diagonal on the base of the unit cell.
Let the diagonal across the cube be y
Pythagoras theorem,
(a^2) + ((a(√2))^2) = (y^2)
(a^2) + 2(a^2) = (y^2) = 3(a^2)
y = a√3
But the diagonal through the cube = 4R (evident from the image in the first attachment)
y = 4R = a√3
a = (4R)/(√3)
QED!!!
Answer:
Step-by-step explanation:
=7 (1+11+111+1111......n)
=7/9 (9+99+999+9999....n)
=7/9 ((10-1)+(10^2-1)+(10^3-1)+....n)
=7/9 ((10+10^2+10^3...n)-(1+1+1+1.....n))
=7/9 ((10 (10^n-1)/(10-1))-n)
Answer: The box would have 99% of its volume taken up.
Step-by-step explanation: The box has dimensions as follows;
Length = 6 inches
Width = 5 inches
Height = 10 inches
Therefore the volume of the box shall become
Volume = L x W x H
Volume = 6 x 5 x 10
Volume = 300 cubic inches
Also a 3 inch cube would have its volume given as follows (
Volume = 3 x 3 x 3 (All sides of a cube has equal lengths)
Volume = 27 cubic inches
To find out how many of 3-inch cubes can fit in, divide 300 by 27 and that equals 11.11.
Hence you can have at most 11 cubes in the box. The total volume of 11 cubes is given as 11 x 27 which equals 297. Therefore, the percentage of the box taken up completely by the cubes is given as;
Percentage = (Volume of cubes/Volume of box) x 100
Percentage = (297/300) x 100
Percentage = 99
Therefore the box would have 99% of its volume taken up by the cubes.
