What is the area of a triangle with vertices at (-4,1), (-7,5) and (0,1)
1 answer:
Answer:
62.1467 square units (correct to four decimal places)
Step-by-step explanation:
Let's say the triangle is;
A(-7,5)
B(-4,1)
C(0,1)
Let's say also that AB = a , BC = b and AC = c
By measurement BC = 4 units , AB = 5 units (applying Pythagorean theorem) and AC = 8.1 units (correct to one decimal place) also through Pythagorean theorem.
Area of this triangle = , where p is half the perimeter of the triangle
p = units
Area = = 62.1467 square units (correct to four decimal places)
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ANSWER
The rule is given by the relation,
EXPLANATION
We need to check and see if there is a constant difference between the y-values.
We can see that, there is a constant difference of 2.
This means that the table represents a linear relationship.
Let the rule be of the form,
Then the points in the table should satisfy the above rule.
So let us plug in
This implies that,
Our rule now becomes,
We again plug in another point say, (-1,-1) in to equation (1) to get,
we solve for m now to obtain,
We now substitute back in to equation (1) to get
The rule is given by the relation,
EXPLANATION
We need to check and see if there is a constant difference between the y-values.
We can see that, there is a constant difference of 2.
This means that the table represents a linear relationship.
Let the rule be of the form,
Then the points in the table should satisfy the above rule.
So let us plug in
This implies that,
Our rule now becomes,
We again plug in another point say, (-1,-1) in to equation (1) to get,
we solve for m now to obtain,
We now substitute back in to equation (1) to get