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stellarik [79]
3 years ago
8

On the number line below, Point B lies somewhere between Points A and C. If AB = \frac{1}{3} AC. Find BC. a 16 b 0 c 8 d 24

Mathematics
1 answer:
ollegr [7]3 years ago
5 0

Answer:

See Explanation

Step-by-step explanation:

The question is incomplete as the number line is not attached.

<em>However, the following will guide you through</em>

Given

AB = \frac{1}{3}AC

Required

Determine BC

First, we need to get the fraction of BC using the following

AB + BC = AC

Substitute \frac{1}{3}AC for AB

\frac{1}{3}AC + BC = AC

Make BC the subject of formula

BC = AC - \frac{1}{3}AC

Take LCM

BC =  \frac{3AC - AC}{3}

BC =  \frac{2AC}{3}

BC =  \frac{2}{3}AC

This implies that you multiply the length of AC by 2/3 to get BC

<em>Take for instance, AC = 24</em>

<em>BC will be:</em>

<em />BC = \frac{2}{3} * 24<em />

<em />BC = \frac{48}{3}<em />

<em />BC = 16<em />

<em />

<em>Or if AC = 12</em>

<em>BC will be:</em>

<em />BC = \frac{2}{3} * 12<em />

<em />BC = \frac{24}{3}<em />

<em />BC = 8<em />

<em />

<em>Or if AC = 36</em>

<em>BC will be:</em>

<em />BC = \frac{2}{3} *36<em />

<em />BC = \frac{72}{3}<em />

<em />BC = 24<em />

<em />

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