Let f(x) = p(x)/q(x), where p and q are polynomials and reduced to lowest terms. (If p and q have a common factor, then they contribute removable discontinuities ('holes').)
Write this in cases:
(i) If deg p(x) ≤ deg q(x), then f(x) is a proper rational function, and lim(x→ ±∞) f(x) = constant.
If deg p(x) < deg q(x), then these limits equal 0, thus yielding the horizontal asymptote y = 0.
If deg p(x) = deg q(x), then these limits equal a/b, where a and b are the leading coefficients of p(x) and q(x), respectively. Hence, we have the horizontal asymptote y = a/b.
Note that there are no obliques asymptotes in this case. ------------- (ii) If deg p(x) > deg q(x), then f(x) is an improper rational function.
By long division, we can write f(x) = g(x) + r(x)/q(x), where g(x) and r(x) are polynomials and deg r(x) < deg q(x).
As in (i), note that lim(x→ ±∞) [f(x) - g(x)] = lim(x→ ±∞) r(x)/q(x) = 0. Hence, y = g(x) is an asymptote. (In particular, if deg g(x) = 1, then this is an oblique asymptote.)
This time, note that there are no horizontal asymptotes. ------------------ In summary, the degrees of p(x) and q(x) control which kind of asymptote we have.
I hope this helps!
Step-by-step explanation:
this is clearly not a linear sequence (the terms don't have the same difference).
so, it has to be a geometric sequence.
the common ratio is r.
s2 = s1 × r
16 = 64 × r
r = 16/64 = 1/4
control :
s3 = s2×r
4 = 16 × 1/4 = 4
correct.
Answer:
8 boxes approx
Step-by-step explanation:
Step one:
given data
One box contains 48 bars
Required
The number of boxes needed for a total of 338 students if each person is to get at least one bar.
Step two:
this can be gotten by dividing 338 by the number of the bar in a box
= 338/48
=7.04
=8 boxes approx
He needs to purchase at least 8 box
