You have to complete the square on this to get it into standard form of a circle. Move the 8 over to the other side because that's part of the radius. Group together the x terms, take half the linear term which is 8, square it and add it in to both sides. Half of 8 is 4, 4 squared is 16, so add in 16 to both sides. I'll show you in a sec. You don't need to do anything to the y squared term. This just means that the center of the circle does not move up or down, only side to side, right or left. Here's your completing the square before we simplify it down to its perfect square binomial.
. Now break down the parenthesis into the perfect square binomial and do the addition of the right:
. This is the standard form of a circle that has a center of (4, 0) and a radius of
Answer:
(D) 2√3
Step-by-step explanation:
From the above question ,we are asked to solve for:
6/√12 −√3
In other to simplify, we would expand the numerator of 6/√12
So we have;
= [6/(√4 ×√3)] - √3
= (6/ 2 ×√3) - √3
= (6/2 × √3) - √3
= (3 ×√3) - √3
= 3√3 - √3
= 2√3
Therefore, the value of 6/√12 −√3 is
option (D) 2√3
Block Y has the smallest acceleration
Answer:
1900
Step-by-step explanation:
let a = total seats
the number of students that filled the theatre can be represented with this equation
0.45 x a = 855
divide both sides by 0.45
a = 855/0.45 = 1900
Answer:
Given - PS is parallel to QR
angle QPS is congruent to angle SRQ
To prove - PQ is congruent to RS
Solution -
In triangle PSQ and SQR
Angle PSQ = Angle SQR ( Interior Angle form by the parallel lines are equal i.e PQ is parallel to QR)
Angle P = Angle R (given)
SQ = SQ ( common)
PSQ = SQR ( prove above)
By ASA Congruence criteria Triangle PQS is congruent to triangle QRS
By CPCT PS is congruent to RS
Hence, Proved
