1answer.
Ask question
Login Signup
Ask question
All categories
  • English
  • Mathematics
  • Social Studies
  • Business
  • History
  • Health
  • Geography
  • Biology
  • Physics
  • Chemistry
  • Computers and Technology
  • Arts
  • World Languages
  • Spanish
  • French
  • German
  • Advanced Placement (AP)
  • SAT
  • Medicine
  • Law
  • Engineering
Aleksandr-060686 [28]
3 years ago
5

What's P squared -1 factorised?

Mathematics
1 answer:
Aleksandr [31]3 years ago
8 0
(p+1) (p-1). solved this on paper . hope it helps .
You might be interested in
What is 4/15 divided by 2/3?
BaLLatris [955]

Answer: 0.4 or 2/5

Hope it helps!

5 0
3 years ago
4x-8=12 when x=-2<br> verify the solution of the equation and explain.
mojhsa [17]

Answer:

Solve in terms of the arbitrary variable x . x = 5 5 = − 2

Step-by-step explanation:

7 0
2 years ago
Geometry math question please help
Triss [41]

A square is a figure with four equal sides and four right angles.In a square the diagonals bisect at right angles .

In the above given options option A is the right answer.

If the diagonals of any parallelogram are perpendicular then the figure is not necessarily a square.

Diagonals are perpendicular in a rhombus too.

A square and Rhombus both have diagonals that are perpendicular.

So it is not a necessary condition for a parallelogram to be a square .

The other options are right .

So option B is the right option that if diagonals are perpendicular is not sufficient to prove the figure to be a square.

6 0
3 years ago
A box in a supply room contains 24 compact fluorescent lightbulbs, of which 8 are rated 13-watt, 9 are rated 18-watt, and 7 are
Marrrta [24]

Answer:

a) There is 17.64% probability that exactly two of the selected bulbs are rated 23-watt.

b) There is a 8.65% probability that all three of the bulbs have the same rating.

c) There is a 12.45% probability that one bulb of each type is selected.

Step-by-step explanation:

There are 24 compact fluorescent lightbulbs in the box, of which:

8 are rated 13-watt

9 are rated 18-watt

7 are rated 23-watt

(a) What is the probability that exactly two of the selected bulbs are rated 23-watt?

There are 7 rated 23-watt among 23. There are no replacements(so the denominators in the multiplication decrease). Then can be chosen in different orders, so we have to permutate.

It is a permutation of 3(bulbs selected) with 2(23-watt) and 1(13 or 18 watt) repetitions. So

P = p^{3}_{2,1}*\frac{7}{24}*\frac{6}{23}*\frac{17}{22} = \frac{3!}{2!1!}*\frac{7}{24}*\frac{6}{23}*\frac{17}{22} = 3*\frac{7}{24}*\frac{6}{23}*\frac{17}{22} = 0.1764

There is 17.64% probability that exactly two of the selected bulbs are rated 23-watt.

(b) What is the probability that all three of the bulbs have the same rating?

P = P_{1} + P_{2} + P_{3}

P_{1} is the probability that all three of them are 13-watt. So:

P_{1} = \frac{8}{24}*\frac{7}{23}*\frac{6}{22} = 0.0277

P_{2} is the probability that all three of them are 18-watt. So:

P_{2} = \frac{9}{24}*\frac{8}{23}*\frac{7}{22} = 0.0415

P_{3} is the probability that all three of them are 23-watt. So:

P_{3} = \frac{7}{24}*\frac{6}{23}*\frac{5}{22} = 0.0173

P = P_{1} + P_{2} + P_{3} = 0.0277 + 0.0415 + 0.0173 = 0.0865

There is a 8.65% probability that all three of the bulbs have the same rating.

(c) What is the probability that one bulb of each type is selected?

We have to permutate, permutation of 3(bulbs), with (1,1,1) repetitions(one for each type). So

P = p^{3}_{1,1,1}*\frac{8}{24}*\frac{9}{23}*\frac{7}{22} = 3**\frac{8}{24}*\frac{9}{23}*\frac{7}{22} = 0.1245

There is a 12.45% probability that one bulb of each type is selected.

3 0
3 years ago
I need help i have 5 minutes left of class i will give brainest if answer make sure to show poof ( If u lie i Will report you) =
kobusy [5.1K]

Answer:

circle question: 69.66

the other question: 66.8

Step-by-step explanation:

For the circle question:

the circle is inscribed in the square, so the diameter of the circle = side of the square

so we need to find the area of square and circle

then do this

square area - circle area

square area(side×side) = 324

circle area(pi×r^2)≈254.469

so shaded region = 69.66

__________

the other question:

we need to find the area of triangle and the area of the rectangle and add them together

A of Triangle (1/2×base×hight) = 34.32

A of rectangle (width × length) = 31.92

add them, so the answer will be = 66.8

4 0
3 years ago
Other questions:
  • Last year sales were 14200. Sales increased 57% this year. how much is the increased
    14·2 answers
  • PLEASE HELP ME I DONT UNDERSTAND THIS QUESTION
    10·1 answer
  • Tiffany is packing her bags for her vacation. She has
    12·2 answers
  • Mr. Chen writes the expression 4 ×
    14·1 answer
  • Manisha bought one pencil for 1.50 paise . how much will 9 pencils cost​
    6·2 answers
  • A composite shape is shown.
    6·2 answers
  • The Martins drove the car from 7 a.m. to 4 p.m. and
    15·1 answer
  • A pyramid and a cone are both 8 centimeters tall and have the same volume.
    14·2 answers
  • Suppose that the height (in centimeters) of a candle is a linear function of the amount of time (in hours) it has been burning.
    6·1 answer
  • PLEASE HELP!! Need by 3/29/22!<br> Find the area of these shapes
    11·1 answer
Add answer
Login
Not registered? Fast signup
Signup
Login Signup
Ask question!