We have to integrate the expression in order to find average rate of change.

Now


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Answer:
NO, as per study, I cant see any other problem than the sample size in the procedure.
From the graph there is a slight quadratic relationship between temperature and number of O-rings.
As in the graph, we can see that above 50°F but below 55°F number of O-rings in 3 but after 55°F as temperature goes on increasing the number of O-rings decreases and remains constant up to 70°F and above 70°F the number of O-rings increases to 2. Hence, we can say that there is a relationship between temperature and number of O-rings.
If we want to fit a linear regression through these seven observations, the slope would be positive as linear regression line passes through the average.
Looking at the relationship, slope must be significantly different from zero as there is a relationship between two variables, where as slope significantly zero implies no relationship. However, we have only seven points so drawing a conclusion is difficult as the nature of the relationship is not clearly visualized by this graph.
I hope this helps you
x+6>=0
x>= -6
Answer:
BC = 25
Step-by-step explanation:
If the base angles are equal, then the sides opposite them are as well.
- 4x + 4 = 6x - 14 Subtract 4x from both sides
- 4x - 4x + 4 = 6x - 4x - 14 Combine
- 4 = 2x - 14 Add 14 to both sides
- 4 + 14 = 2x - 14 + 14 Combine
- 18 = 2x Divide by 2 and switch
- 2x/2 = 18/2 Combine
- x = 9
But that's not what you are asked for. You want the value of 2x + 7
- BC = 2x + 7
- BC = 2*9 + 7
- BC = 25
Using the coefficient of variation, it is found that students were more variable in their marijuana consumption.
<h3>What is the coefficient of variation of a data-set?</h3>
The coefficient of variation of a data-set is given by the <u>division of the standard deviation of the data-set by the mean of the data-set</u>. The higher the coefficient, the more variable the data-set is.
In this problem, for marijuana consumption, the average was 3.74 and the standard deviation was 1.47, hence:

For depression levels, the average was 19.32 and the standard deviation was 3.18, hence:

Due to the higher coefficient, students were more variable in their marijuana consumption.
To learn more about the coefficient of variation, you can take a look at brainly.com/question/26420974