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butalik [34]
3 years ago
13

Can someone help me ASAP please?

Mathematics
2 answers:
arsen [322]3 years ago
5 0

Answer:

67.4°

Step-by-step explanation:

sin x=12/13

x=sin-1(12/13)

x=67.38

give answer correct to 1 decimal places

67.38=67.4°

liq [111]3 years ago
5 0

Answer:

\boxed{Q = 67.4 degrees}

Step-by-step explanation:

Sin Q = \frac{opposite}{hypotenuse}

<u><em>Where opposite = 12, hypotenuse = 13</em></u>

Sin Q = 12/13

Q = Sin^{-1}0.923

Q = 67.4 degrees

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B= c= Please help asap
gladu [14]
B= 20°
and c = 160°

b is equal to the given angle, b = 20°

c is 180 - 20 = 160°
4 0
3 years ago
Find the value of x. Round to the nearest tenth.
serg [7]

Answer:

Where is the equation?

Step-by-step explanation:

8 0
3 years ago
Use estimation to help you choose the correct answer.<br><br> 0.945 x 7.6 =
hoa [83]

Remark

The thing you must not do is write 7.182 as your answer. That is the exact answer found using a calculator.


What to do.

What you should do is multiply two rounded numbers together.

7.6 rounded is 8 roughly


0.945 is almost 1.


Your answer is 8*1 = 8 roughly. This skill is very handy when you are writing a test and you want to see if you've done the question correctly. It is easy to misplace a decimal or put in incorrect digits and this is a quick check on things like that.

7 0
3 years ago
The sum of 3 integers is 194. the sum of the first and second integers exceeds the third by 80. The third integer is 45 less tha
kirill115 [55]
Let
x = first integer
y = second integer
z = third integer
First equation: x + y + z = 194
Second equation: x + y = z + 80
Third equation: z = x - 45

Let's find the values of x, y and z.
Substitute 3rd eq to 1st eq:
x + y + x - 45 = 194
2x + y = 45 + 194
y = -2x + 239

Plug in both we have solved for y and the 3rd eq to the 2nd eq to find x
x + (-2x + 239) = (x - 45) + 80
x - 2x - x = -45 + 80 - 239
-2x = -204
x = -204/-2
x = 102

Solving for y,
y = -2(102) + 239
y = 35

Solving for z,
z = 102 - 45
z = 57
5 0
4 years ago
Need help!!! Plzzz Help mee
andrew-mc [135]
Okay what you need I’ll help you with whatever
8 0
3 years ago
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