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Lera25 [3.4K]
3 years ago
10

Please find x for numbers 1 & 2. Greatly appreciated:)

Mathematics
1 answer:
gavmur [86]3 years ago
7 0

Answer:

1. 14.5

2. 16

Step-by-step explanation:

1. a^2 + b^2 =c^2

20^2 + 21^2 = c^2

400 + 441 = c^2

841 = c^2

\sqrt{841} = \sqrt{c}

29 = c

29/2 = x

14.5 =x

2. c^2-b^2 = a^2

34^2 - 30^2 = a^2

1156 - 900 = a^2

256 = a^2

\sqrt{ 256 } = \sqrt{a}

16 = a

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