1/5(2x - 10) + 4x = -3(1/5x + 4)
0.4x - 2 + 4x = -0.6x - 12
4.4x - 2 = -0.6x - 12
5x - 2 = -12
5x = -10
x = -2
Let the equal sides of the isosceles Δ ABC be x.
Given that the perimeter of Δ ABC = 50m.
Therefore, 2x + AC = 50 --- (1)
It is also given that the perimeter of Δ ABD = 40m.
Therefore, x + BD + AD = 40
BD is the median of the Δ ABC. Therefore, D is the midpoint of AC.
So AD = CD.
Or, AD = 
AC
Therefore, 
Multiply both sides by 2.
2x + 2BD + AC = 80
From (1), 2x + AC = 50.
Therefore, 2BD + 50 = 80
2BD = 80 - 50
2BD = 30
BD = 15m.
Step-by-step explanation:
Answer:
x=0
Step-by-step explanation:
13x-2 = 10x-2
Subtract 10x from each side
13x-10x-2 = 10x-2 -10x
3x-2 = -2
Add 2 for each side
3x-2+2 = -2+2
3x= 0
divide by 3
3x/3 = 0/3
x =0
Answer:
23.6 ft
Step-by-step explanation:
Sketch a right triangle representing this situation. The length of the hypotenuse is 26 ft and the angle of elevation from ground to top of ladder is 65°. The "opposite side" is the reach of the ladder, which we'll call x.
Then:
opp
- sin 65° = ----------
- 26 ft
or (26 ft)(sin 65°) = opp side = height off the ground of top of ladder.
Evaluating this, we get:
(26 ft)(0.906) = 23.56 ft, or, rounded off, 23.6 ft
The ladder reaches 23.6 ft up the side of the building.
