Answer:
1/2
Step-by-step explanation:
Hey there! I'm happy to help!
To find the area of a circle, you square the radius and then multiply by pi (3.14 in our case).
The radius is half of the diameter.
12.6/2=6.3
We square this.
6.3²=39.69
We multiply by 3.14
39.69×3.14=124.6266
We round to the nearest hundredth, giving us an area of 124.63 in².
Now you can find the area of a circle! Have a wonderful day! :D
Answer:
d
Step-by-step explanation:
The question is incomplete, here is the complete question:
Recall that m(t) = m.(1/2)^t/h for radioactive decay, where h is the half-life. Suppose that a 500 g sample of phosphorus-32 decays to 356 g over 7 days. Calculate the half life of the sample.
<u>Answer:</u> The half life of the sample of phosphorus-32 is 
<u>Step-by-step explanation:</u>
The equation used to calculate the half life of the sample is given as:

where,
m(t) = amount of sample after time 't' = 356 g
= initial amount of the sample = 500 g
t = time period = 7 days
h = half life of the sample = ?
Putting values in above equation, we get:

Hence, the half life of the sample of phosphorus-32 is 