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krek1111 [17]
2 years ago
14

A cylinder has a volume of 140 x cubic meters and a height of 14 meters. What is the area of the base?

Mathematics
1 answer:
AleksandrR [38]2 years ago
6 0

Answer: I think it's a

Step-by-step explanation:

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The equation of the function is Y=4x+5.Find the value of y when<br> x=3<br> x=-2
natita [175]
<h2><u>Q</u><u>u</u><u>e</u><u>s</u><u>t</u><u>i</u><u>o</u><u>n</u>:-</h2>

The equation of the function is y = 4x + 5. Find the value of y when

x = 3

x = -2

<h2><u>A</u><u>n</u><u>s</u><u>w</u><u>e</u><u>r</u>:-</h2>

<h3>Given:-</h3>

y = 4x + 5 [Equation]

<h3>To Find:-</h3>

The value of y when x = 3 , x = -2

<h2>Solution:-</h2>

y = 4x + 5 [Given equation]

\therefore When x = 3 ,

y = 4 × 3 + 5 [Value of x is 3]

y = 12 + 5

<h3>y = 17 [Answer]</h3>

Again, when x = -2 ,

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y = -8 + 5

<h3>y = -3 [Answer]</h3>

8 0
3 years ago
I can't solve it, so, here goes nothin'. "Some people are on a train, 19 people get off at one stop, then, the next one 13. Now
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2 years ago
If arc SQ = 84° and ∠RPS = 26°, what is the measure of arc RS? need answer asap thank you
Lera25 [3.4K]

Answer:

arc\ RS=136\°

Step-by-step explanation:

we know that

The measurement of the external angle is the semi-difference of the arcs which comprises

In this problem

m∠RPS=26\° ------> external angle

so

m∠RPS=\frac{1}{2}(arc\ RS-arc\ SQ)

we have

m∠RPS=26\°

arc\ SQ=84\°

substitute the values

26\°=\frac{1}{2}(arc\ RS-84\°)

Solve for arc RS

52\°=(arc\ RS-84\°)

arc\ RS=52\°+84\°=136\°

3 0
3 years ago
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Solve for x. -4≤2x+6&lt;12
-BARSIC- [3]

-4≤2x+6<12

-6        -6   -6

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The standard diameter of a golf ball is 42.67 mm. A golf ball factory does quality control on the balls it manufactures. Golf ba
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The lower end of the range is
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