Let
denote the rocket's position, velocity, and acceleration vectors at time
.
We're given its initial position

and velocity

Immediately after launch, the rocket is subject to gravity, so its acceleration is

where
.
a. We can obtain the velocity and position vectors by respectively integrating the acceleration and velocity functions. By the fundamental theorem of calculus,


(the integral of 0 is a constant, but it ultimately doesn't matter in this case)

and



b. The rocket stays in the air for as long as it takes until
, where
is the
-component of the position vector.

The range of the rocket is the distance between the rocket's final position and the origin (0, 0, 0):

c. The rocket reaches its maximum height when its vertical velocity (the
-component) is 0, at which point we have


Answer:
你看chart的triangle你看the dimension
Step-by-step explanation:
Here you would want to use the sine function, since it’s making a triangle with the ground, and length of the string, the height to the kite. This can be found by 65sin(70°) which is ≈ 61.08 meters
Answer:
You can look at the screenshot
Step-by-step explanation:
So one point of the line is (0, -4) and another point is (4/3, 0). Plot these points on a graph and draw a line.
0, -4 is from making x = 0, and then 4/3, 0 is from making y = 0.
I think is letter A l hope it works.