Answer:
Given: Quadrilateral P QR S is a rectangle.
To prove :PR= Q S
Construction : Join PR and Q S.
Proof: In Rectangle PQRS, and
→ taking two triangles PSR and Δ QRS
1. PS = Q R
2. ∠ PS R = ∠ Q RS [Each being 90°]
3. S R is common.
→ ΔP SR ≅ Δ Q RS → [Side-Angle-Side Congruency]
∴ PR =Q S [ corresponding part of congruent triangles ]
Hence proved.
Answer and Step-by-step explanation:
The parent function, f(x) = |x|, has no transformations applied to it.
When the number is with the x, it translates the graph horizontally. <->
When the number is outside of the absolute box, it translates the graph vertically. ^ V
When the number is multiply the absolute box on the outside with the x inside, it scales the graph.
So, first lets apply the translations of horizontal and vertical shift.
The graph translated 1 units downwards.
The graph translates 2 units to the right.
g(x) = |x - 2| - 1
We subtract the 2 because that makes it go right, while if we added it would go left.
Now for the scale.
The lines have a slope of , so that is what we are multiplying.
<u> g(x) = </u><u>|x - 2| - 1</u>
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<u>^That is your transformed function.</u>
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