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Tanya [424]
4 years ago
10

In the following equations a and b are equal. which number could be substituted for both a and b to make both equations correct?

Mathematics
1 answer:
Nikitich [7]4 years ago
7 0
 Considering the first equation 15 × 0 = -36 + a 
 15 × 0 = 0
therefore, -36 + a =0
In the second equation
 24 × 8 × 0 = 36 - b
Consider the LS 
24 × 8 × 0 = 0
Therefore, 36 - b = 0
we are left with the two equations,
 36 - b = 0
-36 + a = 0
then, we calculate the number that can be substituted to satisfy the two equations.
solving the equations
 b = 36, and a = 36
Therefore, 36 is the number that can be used to substitute a and b in the equations 

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The weights that are significantly low z₁ = 5.361308 grams and significantly high z₂ = 5.48057 grams  

<h3>What is Z -score?</h3>

A Z-score is defined as the fractional representation of data point to the mean using standard deviations.

z -score = (z₁ - μ₀) / σ

where μ₀  is the mean and σ the standard deviation.

Consider a value to be significantly low if its z score is less than or equal to -2 or consider a value to be significantly high if its z score is greater than or equal to 2.

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⇒ (-2)(0.05421) = z₁ - 5.37215

⇒ -0.10842 = z₁ - 5.37215

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And if z = 2

Here μ₀ = 5,37215 and σ = 0.05421

Substitute z -score = 2

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Therefore, the weights that are significantly low z₁ = 5.361308 grams and significantly high z₂ = 5.48057 grams

Learn more about the z-score here:

brainly.com/question/13793746

#SPJ4

Your question is incomplete, probably the complete question is:

A data set lists the weights​ (grams) of a type of coin. Those weights have a mean of 5.37215 g and a standard deviation of .05421 g. Identify the weights that are significantly low or significantly high.

Consider a value to be significantly low if its z score is less than or equal to -2 or consider a value to be significantly high if its z score is greater than or equal to 2.

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