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4 years ago

There were fifteen bales of hay in the barn and twenty - eight bales in the shed. Sam

Mathematics

1 answer:

Triss [41]4 years ago

7 0

Answer:

Step-by-step explanation:

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Which of the following equations could be solved for a radius? Select all that apply.

zalisa [80]

Answer:

A = π · (r²)

Step-by-step explanation:

$A =$ π · r² is the area of a circle.

While π · r² · h can also give you the radius, it can only do so for the Volume $V$ , not the Area $A$ .

$V=lwh$ doesn't really apply for a circular object, as it requires the length and width. For circular objects, both are equal to the diameter of the object, and 2² · r² · h does not equal the Volume.

$V=$ π · r³ seems awfully like the volume of a sphere, but there's something missing. The true volume of a sphere is $V=\frac{4}{3}$ · π · r³, not $V=$ π · r³.

$A=\frac{1}{2}*b*h$ only applies for triangles.

3 0

3 years ago

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3n-8+2(5n+3)=8n+5+4n

DaniilM [7]

<span>3n-8+2(5n+3)=8n+5+4n first I will do the multiplication
3n-8+10n+6=8n+5+4n Now I will simplify
13n -2 = 12n +5 Now I will add 2 to both sides
13n = 12n + 7 then I subtract 12n from both sides
n = 7</span>

7 0

4 years ago

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At the beginning of an experiment, a scientist has 300 grams of radioactive goo. After 150 minutes, her sample has decayed to 37

monitta

Answer:

Half-life of the goo is 49.5 minutes

$G(t)= 300e^{-0.014t}$

191.7 grams of goo will remain after 32 minutes

Step-by-step explanation:

Let $M_0\,,\,M_f$ denotes initial and final mass.

$M_0=300\,\,grams\,,\,M_f=37.5\,\,grams$

According to exponential decay,

$\ln \left ( \frac{M_f}{M_0} \right )=-kt$

Here, t denotes time and k denotes decay constant.

$\ln \left ( \frac{M_f}{M_0} \right )=-kt\\\ln \left ( \frac{37.5}{300} \right )=-k(150)\\-2.079=-k(150)\\k=\frac{2.079}{150}=0.014$

So, half-life of the goo in minutes is calculated as follows:

$\ln \left ( \frac{50}{100} \right )=-kt\\\ln \left ( \frac{50}{100} \right )=-(0.014)t\\t=\frac{-0.693}{-0.014}=49.5\,\,minutes$

Half-life of the goo is 49.5 minutes

$\ln \left ( \frac{M_f}{M_0} \right )=-kt\Rightarrow M_f=M_0e^{-kt}$

So,

$G(t)= M_f=M_0e^{-kt}$

Put $M_0=300\,\,grams\,,\,k=0.014$

$G(t)= 300e^{-0.014t}$

Put t = 32 minutes

$G(32)= 300e^{-0.014(32)}=300e^{-0.448}=191.7\,\,grams$

7 0

3 years ago

Which quadratic function in vertex form can be represented by the graph that has a vertex at (3, -7) and passes through the poin

yarga [219]

$~~~~~~\textit{vertical parabola vertex form} \\\\ y=a(x- h)^2+ k\qquad \begin{cases} \stackrel{vertex}{(h,k)}\\\\ \stackrel{"a"~is~negative}{op ens~\cap}\qquad \stackrel{"a"~is~positive}{op ens~\cup} \end{cases} \\\\[-0.35em] ~\dotfill$

$\begin{cases} h=3\\ k=-7 \end{cases}\implies y=a(x-3)^2-7\qquad \textit{we also know that} \begin{cases} x=1\\ y=-10 \end{cases} \\\\\\ -10=a(1-3)^2-7\implies -3=a(-2)^2\implies -3=4a\implies -\cfrac{3}{4}=a \\\\[-0.35em] ~\dotfill\\\\ ~\hfill y=-\cfrac{3}{4}(x-3)^2-7~\hfill$

5 0

2 years ago

7b ÷ 12 = 4.2 what does b =

Luda [366]

7b/12=4.2
7b=50.4
b=7.2

hope this helps

3 0

4 years ago

Read 2 more answers