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earnstyle [38]
3 years ago
13

What value of x satisfies the equation 7x+1=2.4 ?

Mathematics
2 answers:
omeli [17]3 years ago
8 0
<em>The answer you are looking for is: </em>
<em>7x+1=2.4 </em>
<em>7x+1</em><u><em>-1</em></u><em> =2.4</em><u><em>-1</em></u><em> </em>
<em>7x=1.4 </em>
<em>\frac{7x}{7}=\frac{1.4}{7} </em>
<em><u>x=0.2 </u></em>
<em>Hope that helps!! </em>
<em>Have a wonderful day!!</em>
yuradex [85]3 years ago
3 0
5.6 because    7=1=8          so    8-2.4=5.6

hope this helped please leave a thank you
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Jet001 [13]
<h2>Hello!</h2>

The answers are:

B.   \frac{-3-\sqrt{29}}{2}

C.   \frac{-3+\sqrt{29}}{2}

<h2>Why?</h2>

We can use the quadratic equation to find the two values of x that are roots of the given equation. We must remember that most of the quadratic equations have two roots, however, we could find quadratic equations with just one root or even with no roots, at least in the real numbers.

Quadratic equation:

\frac{-b+-\sqrt{b^{2}-4ac} }{2a}

So,

From the given equation we have:

a=1\\b=3\\c=-5

Substituting it into the quadratic equation to find the roots, we have:

\frac{-b+-\sqrt{b^{2}-4ac} }{2a}=\frac{-3+-\sqrt{3^{2}-4*1*-5} }{2*1}\\\\\frac{-3+-\sqrt{3^{2}-4*1*-5} }{2*1}=\frac{-3+-\sqrt{9+20} }{2}\\\\\frac{-3+-\sqrt{29}}{2}

So,

x_{1}=\frac{-3-\sqrt{29}}{2}\\\\x_{2}=\frac{-3+\sqrt{29}}{2}

Hence, the correct options are B and C.

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