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Firlakuza [10]
3 years ago
11

In a large population, 81% of the households have cable tv. A simple random sample of 196 households is to be contacted and the

sample proportion computed. What is the mean and standard deviation of the sampling distribution of the sample proportions
Mathematics
1 answer:
IrinaK [193]3 years ago
4 0

Answer:

0.028

Step-by-step explanation:

Given that :

Population = Large

Household with cable TV = 81%

Sample size (n) = 196

The mean of sampling distribution (μx) = p = 81% = 81/100 = 0.81

The standard deviation of sampling distribution

Standard deviation (σ) :

σ = √[(p*(1 - p)) / n]

= √(0.81 * (1 - 0.81)) / 196

= √(0.1539 / 196)

= √0.0007852

= 0.0280214

= 0.028

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Step-by-step explanation:

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First, in order to solve this exercise it is important to remember that, by definition:

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