In a large population, 81% of the households have cable tv. A simple random sample of 196 households is to be contacted and the
sample proportion computed. What is the mean and standard deviation of the sampling distribution of the sample proportions
1 answer:
Answer:
0.028
Step-by-step explanation:
Given that :
Population = Large
Household with cable TV = 81%
Sample size (n) = 196
The mean of sampling distribution (μx) = p = 81% = 81/100 = 0.81
The standard deviation of sampling distribution
Standard deviation (σ) :
σ = √[(p*(1 - p)) / n]
= √(0.81 * (1 - 0.81)) / 196
= √(0.1539 / 196)
= √0.0007852
= 0.0280214
= 0.028
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