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Elden [556K]
3 years ago
7

Please help with this problem

Mathematics
1 answer:
IRISSAK [1]3 years ago
3 0
The slope is 2/3 because 3 - 1 = 2 and 0 - -3 = 3
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The heights of women aged 20 to 29 are approximately normal with mean 64 inches and standard deviation 2.7 inches. men the same
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<span>To find the z-scores, find the difference in the number of inches for each value from the mean and then divide that by the standard deviation. For women at 72 inches (6'), this would be (72-64) / 2.7, or a z-score of +2.963. For a male at 72 inches, this would be (72-69.3)/2.8, or +0.964. This shows that the woman at 6 feet tall is more rare in the distribution than a man at 6 feet tall.</span>
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A


Step-by-step explanation:


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3 years ago
If a manufacturer conducted a survey among randomly selected target market households and wanted to be 95​% confident that the d
katen-ka-za [31]

Answer:

We need a sample size of least 119

Step-by-step explanation:

In a sample with a number n of people surveyed with a probability of a success of \pi, and a confidence level of 1-\alpha, we have the following confidence interval of proportions.

\pi \pm z\sqrt{\frac{\pi(1-\pi)}{n}}

In which

z is the zscore that has a pvalue of 1 - \frac{\alpha}{2}.

The margin of error is:

M = z\sqrt{\frac{\pi(1-\pi)}{n}}

95% confidence level

So \alpha = 0.05, z is the value of Z that has a pvalue of 1 - \frac{0.05}{2} = 0.975, so Z = 1.96.

Sample size needed

At least n, in which n is found when M = 0.09

We don't know the proportion, so we use \pi = 0.5, which is when we would need the largest sample size.

M = z\sqrt{\frac{\pi(1-\pi)}{n}}

0.09 = 1.96\sqrt{\frac{0.5*0.5}{n}}

0.09\sqrt{n} = 1.96*0.5

\sqrt{n} = \frac{1.96*0.5}{0.09}

(\sqrt{n})^{2} = (\frac{1.96*0.5}{0.09})^{2}

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Rounding up

We need a sample size of least 119

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3 years ago
Look at the picture of a scaffold used to support construction workers. The height of the scaffold can be changed by adjusting t
timama [110]

Step-by-step explanation:

<u>Using Pythagorus theorem</u> :

(A)

PR =  \sqrt{ {PQ}^{2}  +  {QR}^{2} }

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(B)

QR  =   \sqrt{ {PQ}^{2}  +  {PR}^{2} }  =  \sqrt{196 +324 }  = 22.8 \: cm

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3 years ago
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