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velikii [3]
3 years ago
9

Which exponential function matches the table?

Mathematics
1 answer:
sveticcg [70]3 years ago
8 0

Answer:

b

Step-by-step explanation:since i helped can i have brainlist please :D

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agasfer [191]

Answer:

7/4 which could also be written as 1 and 3/4

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3 years ago
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ANSWER FAST PLZZZ Which polygons are congruent? Select each correct answer. Two right scalene triangles labeled D E F and P Q R.
Shalnov [3]
A is congruent
B is congruent
C is congruent
D is not congruent
And E is the same picture as B so it is also congruent
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I need help with number 3
Sauron [17]

Answer:

5√3 or

8.66 to the nearest hundred.

Step-by-step explanation:

Length of each line of the triangle = 30/3 = 10.

The altitude, side and 1/2 base make a right triangle.

So by Pythagoras:

10^2 = 5^2 + h^2   where h = altitude.

h^2 = 100 - 25 = 75

h = √75 = 5√3.

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3 years ago
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Lelu [443]

axis of symmetry is the dashed red lines of the equation/parabola. The symmetry is basically like the mirror of both sides of a parabola.

<h2>ANSWER: x = 2</h2>

7 0
3 years ago
Whose good at Geomtry, specifically trigonometry?!!?
ddd [48]

Answer:

C. 2.8 miles per minute

Step-by-step explanation:

The mnemonic SOH CAH TOA reminds you that ...

... Tan = Opposite/Adjacent

In the relevant triangle, the side opposite the angle at the observer is the altitude of the airplane, 2 miles. The side adjacent is the horizontal distance to the airplane. At the first observation, that distance (d1) is ...

... tan(40°) = (2 mi)/d1

At the second observation, the horizontal distance to the airplane (d2) is ...

... tan(50°) = (2 mi)/d2

Solving for d1 and d2 and finding the difference (∆d), we have ...

... d1 = (2 mi)/tan(40°)

... d2 = (2 mi)/tan(50°)

... ∆d = d1 -d2 = (2 mi)(1/tan(40°) -1/tan(50°) ≈ 2·(1.1918 -0.8391) mi

... ∆d ≈ 2°0.3526 mi ≈ 0.7053 mi

This distance was flown by the plane in 15 seconds, so it will travel 4 times this distance in 60 seconds (1 minute).

... ∆d/∆t = (0.7053 mi)/(1/4 min) = 4·0.7053 mi/min ≈ 2.8 mi/min

7 0
4 years ago
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