Answer:
![g(x)=-2\sqrt[3]x](https://tex.z-dn.net/?f=g%28x%29%3D-2%5Csqrt%5B3%5Dx)
or

Step-by-step explanation:
Given
![f(x) = \sqrt[3]x](https://tex.z-dn.net/?f=f%28x%29%20%3D%20%5Csqrt%5B3%5Dx)
Required
Write a rule for g(x)
See attachment for grid
From the attachment, we have:


We can represent g(x) as:

So, we have:
![g(x) = n * \sqrt[3]x](https://tex.z-dn.net/?f=g%28x%29%20%3D%20n%20%2A%20%5Csqrt%5B3%5Dx)
For:

![2 = n * \sqrt[3]{-1}](https://tex.z-dn.net/?f=2%20%3D%20n%20%2A%20%5Csqrt%5B3%5D%7B-1%7D)
This gives:

Solve for n


To confirm this value of n, we make use of:

So, we have:
![-2 = n * \sqrt[3]1](https://tex.z-dn.net/?f=-2%20%3D%20n%20%2A%20%5Csqrt%5B3%5D1)
This gives:

Solve for n


Hence:
![g(x) = n * \sqrt[3]x](https://tex.z-dn.net/?f=g%28x%29%20%3D%20n%20%2A%20%5Csqrt%5B3%5Dx)
![g(x)=-2\sqrt[3]x](https://tex.z-dn.net/?f=g%28x%29%3D-2%5Csqrt%5B3%5Dx)
or:

Answer:
Step-by-step explanation:Given that the numerator of a given fraction is 4 less than its denominator.
Also given that 3 is subtracted from the numerator and 5 is added to the denominator, the fraction becomes one by fourth .
Let the fraction be
Since the numerator of a given fraction is 4 less than its denominator we have,
Numerator=Denominator-4
⇒ a=b-4
Since 3 is subtracted from the numerator and 5 is added to the denominator, the fraction becomes one by fourth we have
4(a-3)=1(b+5)
4a-12=b+5
4a-b=17
4(b-4)-b=17 ( ∵ a=b-4)
4b-16-b=17
3b=17+16
3b=33
⇒ b=11
Now put b=11 in a=b-4 we get
a=11-4
⇒ the fraction is a/b=7/11
B.5 and I’m just guessing cause I need something answered
An odd number ends in 1, 3, 5, 7, or 9.
3x-15+2x-2
=5x-17
use the distribution property