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Airida [17]
3 years ago
9

Find csc 0 if sin 0 = 5/6

Mathematics
1 answer:
Bezzdna [24]3 years ago
3 0
Csc is the reciprocal of sin, so csc 0 is 6/5
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Mariah prepared 5 quesadillas she wants to show them equally among 8 of her neighbors how much of a quesadilla will each neighbo
sattari [20]

Each neighbor will receive 5/8 of a quesadilla.

5 0
2 years ago
Which symbol can be used to correctly compare the two fractions? Use > , < , or =. Enter your answer in the box. 75100 34
Bad White [126]

75100 > 34

75100 is greater than 34

4 0
2 years ago
-3(-7) I need this asap pls help me
7nadin3 [17]

Hi there! Hopefully this helps!

-------------------------------------------------------------------------------------------------

<h2>Answer: \boxed{21}</h2><h2 /><h2>~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~</h2>

When you multiply two negatives (-, -,), you are gonna get a positive(+)

<em>[Like making a cross out of two lines].</em>

-3(-7) = +3(+7)

<h2>Since 3(7) normally <u>equals 21</u>, that would be the answer for this case.</h2>

3 0
3 years ago
Read 2 more answers
A basketball player scores 28 points in
Dmitriy789 [7]

Answer:

d) 80

Step-by-step explanation:

(35% = 0.35)

equation:

⇒ 0.35x = 28

divide 0.35 on both sides

⇒ \frac{0.35x}{0.35} = \frac{28}{0.35}

solve:

⇒ x = 80

7 0
2 years ago
For the polynomial function ƒ(x) = −x6 + 3x4 + 4x2, find the zeros. Then determine the multiplicity at each zero and state wheth
murzikaleks [220]

There is a multiple zero at 0 (which means that it touches there), and there are single zeros at -2 and 2 (which means that they cross). There is also 2 imaginary zeros at i and -i.


You can find this by factoring. Start by pulling out the greatest common factor, which in this case is -x^2.


-x^6 + 3x^4 + 4x^2

-x^2(x^4 - 3x^2 - 4)


Now we can factor the inside of the parenthesis. You do this by finding factors of the last number that add up to the middle number.


-x^2(x^4 - 3x^2 - 4)

-x^2(x^2 - 4)(x^2 + 1)


Now we can use the factors of two perfect squares rule to factor the middle parenthesis.


-x^2(x^2 - 4)(x^2 + 1)

-x^2(x - 2)(x + 2)(x^2 + 1)


We would also want to split the term in the front.


-x^2(x - 2)(x + 2)(x^2 + 1)

(x)(-x)(x - 2)(x + 2)(x^2 + 1)


Now we would set each portion equal to 0 and solve.


First root

x = 0 ---> no work needed


Second root

-x = 0 ---> divide by -1

x = 0


Third root

x - 2 = 0

x = 2


Forth root

x + 2 = 0

x = -2


Fifth and Sixth roots

x^2 + 1 = 0

x^2 = -1

x = +/- \sqrt{-1}

x = +/- i

7 0
3 years ago
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