Question

Need help anyone know how to do this

Answer 1

Answer:

ΔABC has: AD=DB

                  AE = EC

=> DE is the median line of ΔABC

=> DE // BC

=> m∠AED = m∠ECF = 32°

.

Step-by-step explanation:

Answer 2

Answer:

∠ ECF = 32°

Step-by-step explanation:

DE is the midsegment of Δ ABC and is therefore parallel to the third side BC.

Since DE and BC are parallel lines, then

∠ ECF and ∠ AED are congruent ( corresponding angles ) , thus

∠ ECF = ∠ AED = 32°