Question

Which sequence of transformations proves that shape I is similar to shape II

Answer 1

Answer: C. a reflection across the x-axis, and then a dilation by a scale factor of 2

Step-by-step explanation:

Coordinates of image I are (3,-2),(3,-3),(4,-1) and (6,-3)

Coordinates of image II are (6,4),(6,6),(8,2) and (12,6)

After reflection across x axis polarity of coordinates of y axis change(opposite sign)

Thus  (x,y)→(x,-y)

(3,-2)→(3,2)

,(3,-3)→(3,3)

,(4,-1) →(4,1)

and (6,-3)→(6,3)

Then after dilation by scale factor of 2 (Multiply 2 to both the x and y coordinates of the points after reflection)

Thus  (x,y)→(2x,2y)

(3,2)→(6,4)

,(3,3)→(6,6)

,(4,1) →(8,2)

and (6,3)→(12,6)

Which are the coordinates of image I.

Thus C is the right option.

Answer 2

C. a reflection across the x-axis, and then a dilation by a scale factor of 2