Question

A man and his wife go shopping. They begin with $200 total. First, they stop for lunch, spending $15.00. Then, they buy three items at $20.00 each. Later, the wife spends twice what her husband spends. They return home with $20.00 cash. How much did the wife spend?

Answer 1

Amount spent by the wife is $70

Step-by-step explanation:

Given:

the total amount  = $200

Amount spent on Lunch = $15.00

They buy three items at $20.00 each

The wife spends twice what her husband spends

They return home with $20.00 cash.

To Find:

Amount spent by the wife  = ?

Solution:

Initially after spending $15.00 on lunch they balance cash with them will be

200 - 15.00 = $185

Then they are buy 3 items each of which costs $20.00

So the balance after buying the 3 items will be

= 200 - 3(20)

= 185- 60.00

= $125

Now the wife is spending twice what her husband spends

so let the amount spent be the husband be x then the amount spent by the wife will be 2x.

Now  after spending 2x+x amount they are  left with $20.00

that is

125 -2x+x  = 20

125 -3x = 20

125 -20 = 3x

105 = 3x

$x = \frac{105}{3}$

x = 35

So the wife will be spending 2(35) = $70