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3 years ago

Which expression is equivalent to sin

Mathematics

1 answer:

Scilla [17]3 years ago

4 0

Answer:

sin(-pi/2) = -1

Step-by-step explanation:

sin (pi/12) cos((7pi)/12) -cos (pi/12) sin((7pi)/12) = -1

cos(-pi/2) = 0

sin(-pi/2) = -1

cos((2pi)/3) = -1/2

sin((2pi)/3) = (√3)/2

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X + 6 = 2x - 8 x= solve for x

nata0808 [166]

Step-by-step explanation:

x + 6 = 2x - 8

1. Subtract 2x from both sides

x - 2x + 6 = 2x - 2x - 8

2. Simplify

-x + 6 = -8

3. Now, subtract 6 from both sides

-x + 6 - 6 = -8 - 6

4. Simplify

-x = -14

5. Divide both sides by -1 because you would want the x by itself instead of having -x

-1x/-1 = -14/-1

6. Simplify

x = 14 <------ Answer

Hope that helped!!

~Shane

8 0

4 years ago

I need help plz plz plz plz

goblinko [34]

Answer:

1. n-5....... 2.v+3 and v- 2

8 0

3 years ago

The equation of a circle is given below. Identify the center and radius. Then graph the circle.

Blizzard [7]

Answer:

Center = (3, 0)
Radius = 3
Graph = see below

Concept:

Here, we need to know the idea of the circle equation.

Circle equation: (x - h)² + (y - k)² = r²

(h, k) = center

r = radius

x = variable

y = variable

Solve:

Given expression

(x - 3)² + y² = 9

Find the point of the center

(h, k) = $\boxed{(3,0)}$

Find the length of the radius

r² = 9

$\boxed{r=3}$

Hope this helps!! :)

Please let me know if you have any questions

3 0

3 years ago

Read 2 more answers

Determine whether the pair of equations represent parallel lines, perpendicular lines, or neither.

Ivahew [28]

Answer:

Parallel

Step-by-step explanation:

Parallel lines have the same slope but different y-intercepts. If you multiply the top equation by 2, you get:

2(12x + 4y = 16)

24x + 8y = 32

This shows that both lines have the same slope, but then you find the y-intercepts, they are different:

1st equation y-int = 4

2nd equation y-int = 9/2 or 4.5

6 0

3 years ago

What is the domain of the function y=in(x+2) x<-2 x>-2 x<2 x> x<-2 x>-2 x<2 x>2

aev [14]

For this case we must find the domain of the following function:

$y = ln (x + 2)$

By definition, the domain of a function is given by all the values for which the function is defined.

In this case, the argument of the expression must be greater than 0 to be defined.

$x + 2> 0\\x> -2$

Thus, the domain of the function is given by all the values of x greater than -2.

Answer:

Domain: $x> -2$

4 0

3 years ago