Solving the given inequality for d, we get...
6d + 15 < 50
6d + 15-15 < 50-15 <<-- subtract 15 from both sides
6d < 35
6d/6 < 35/6 <<--- divide both sides by 6
d < 5.83
Which means that d can be any of the values in this set: {0, 1, 2, 3, 4, 5}
The smallest d can be is 0. In this scenario, Jeremy pays the $15 registration but doesn't rent the camera at all
The largest d can be is 5. In this scenario, Jeremy rents the camera for 5 days
Any larger value of d is not allowed as it would make the total cost go over $50
Notice how I'm rounding down regardless how close 5.83 is to 6
Its A, all y-values are less than -3x+5. also consider root by setting -3x+5=0
x=5/3 is positive so its the first one
Answer:
Step 1: Transpose everything to one side
12. x²+16x+15-10x+4=0
Step 2: Add the like terms
x² + (16x - 10x) + 15 + 4=0
x² + 6x + 19=0
Step 3: Use the quadratic formula to get the value(s) of x.
a=1 b=6 c=19
therefore, x=... or x
I'm assuming the question looks like this?
If so then the answer should be:
Hope this helps!
