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Harrizon [31]
3 years ago
11

Plsss answer everything you know I need the answer ASAP

Mathematics
2 answers:
Evgesh-ka [11]3 years ago
8 0

1. bobby would be 21 and chris 18.


tamaranim1 [39]3 years ago
8 0

1) Answers: Bobby = 22, Chris = 19

<u>Explanation:</u>

                   This year         Last year

Bobby:      3 + x              3 + x - 1   = 2 + x

 Chris:         x                       x - 1

Bobby (last year) + Chris (last year) = sum (last year)

       2 + x             +          x - 1            =       39

2 + x + x - 1 = 39

2 + 2x - 1 = 39

2x + 1 = 39

2x = 38

x = 19

Bobby (this year): 3 + x   = 3 + 19   = 22

Chris (this year):   x = 19

******************************************************************

2. Answers: Beth = 25, Celeste = 30

<u>Explanation:</u>

                  This year          Next year

Beth:             x - 5               x - 5 + 1   = x - 4

Celeste:          x                        x + 1

Beth (next year) + Celeste (next year) = sum (next year)

         x - 4           +           x + 1               =     57

x - 4 + x + 1 = 57

2x - 3 = 57

2x = 60

x = 30

Beth (this year): x - 5   = 30 - 5   = 25

Celeste: x = 30

******************************************************************

3. Answers: Donna = 38, brother = 50

<u>Explanation:</u>

                  This year             in 2 years

Donna:         x - 12                  x - 12 + 2       and       (x + 2)/2 + 14

brother:          x                           x + 2

Donna (in 2 years) = Donna (in 2 years)

        x - 10          =         (x+2)/2 + 14

x - 24 = (x+2)/2

2x - 48 = x + 2

x = 50

Donna (this year): x - 12    = 50 - 12   = 38

brother: x = 50

******************************************************************

4. Answers: Freddie = 40, Elena = 8

<u>Explanation:</u>

                  This year             in 4 years

Freddie:          5x                     5x + 4      and       3(x + 4) + 8

Elena:               x                       x + 4

Freddie (in 4 years) = Freddie (in 4 years)

          5x + 4            =        3(x + 4) + 8  

5x + 4 = 3x + 12 + 8

2x = 16

x = 8

Freddie: 5x   = 5(8)   = 40

Elena: x   = 8

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3 years ago
D is between C and E, CD = x 2 , CE = 32-2x, and DE = 12x. Find CD, DE, and CE.
Gemiola [76]

Answer:

  • CD = 4
  • DE = 24
  • CE = 28

Step-by-step explanation:

The segment addition theorem tells you ...

  CD +DE = CE

  x^2 +12x = 32 -2x

Subtract the right side to put this in standard form.

  x^2 +14x -32 = 0

  (x +16)(x -2) = 0

  x = -16 or 2

In order for DE to have a positive length, we must have x > 0. So ...

  CD = x^2 = 2^2 = 4

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3 0
3 years ago
Twice a number, decreased by nineteen
anzhelika [568]
2n-19 I think is the answer :3
5 0
3 years ago
Read 2 more answers
QUICK PLEASE ANSWER
Mila [183]

Answer:

63/80 and 7/4 * 9/20

Step-by-step explanation:

7/8 * 9/10 = 63/80

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8 0
2 years ago
A Government company claims that an average light bulb lasts 270 days. A researcher randomly selects 18 bulbs for testing. The s
Fofino [41]

Answer:

31.92% probability that 18 randomly selected bulbs would have an average life of no more than 260 days

Step-by-step explanation:

To solve this question, we need to understand the normal probability distribution and the central limit theorem.

Normal probability distribution

When the distribution is normal, we use the z-score formula.

In a set with mean \mu and standard deviation \sigma, the zscore of a measure X is given by:

Z = \frac{X - \mu}{\sigma}

The Z-score measures how many standard deviations the measure is from the mean. After finding the Z-score, we look at the z-score table and find the p-value associated with this z-score. This p-value is the probability that the value of the measure is smaller than X, that is, the percentile of X. Subtracting 1 by the pvalue, we get the probability that the value of the measure is greater than X.

Central Limit Theorem

The Central Limit Theorem estabilishes that, for a normally distributed random variable X, with mean \mu and standard deviation \sigma, the sampling distribution of the sample means with size n can be approximated to a normal distribution with mean \mu and standard deviation s = \frac{\sigma}{\sqrt{n}}.

For a skewed variable, the Central Limit Theorem can also be applied, as long as n is at least 30.

For a proportion p in a sample of size n, the sampling distribution of the sample proportion will be approximately normal with mean \mu = p and standard deviation s = \sqrt{\frac{p(1-p)}{n}}

In this question, we have that:

\mu = 270, \sigma = 90, n = 18, s = \frac{90}{\sqrt{18}} = 21.2

What is the probability that 18 randomly selected bulbs would have an average life of no more than 260 days?

This is the pvalue of Z when X = 260. So

Z = \frac{X - \mu}{\sigma}

By the Central Limit Theorem

Z = \frac{X - \mu}{s}

Z = \frac{260 - 270}{21.2}

Z = -0.47

Z = -0.47 has a pvalue of 0.3192.

31.92% probability that 18 randomly selected bulbs would have an average life of no more than 260 days

5 0
3 years ago
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