If a plant cell had a mutation such that the cyclic electron flow is observed at a much higher rate, which photosystem is most likely mutated such that energy is absorbed at a lower rate?
PSI
PSII
Answer:
PSII
Explanation:
Non-cyclic phosphorylation involves both PSI and PSII. The process starts with the splitting of water and excitation of electrons of the reaction center of PSII upon the absorption of solar energy at the wavelength of 680 nm. Any mutation in PSII would not allow the non-cyclic phosphorylation to occur when only cyclic phosphorylation would occur. The process of cyclic phosphorylation includes only PS I. Its reaction center absorbs maximum light at 700 nm and is cycled back while supporting ATP synthesis. Therefore, if a plant performs cyclic phosphorylation at a higher rate and absorbs less energy, this means that mutation was in PSII.
Answer:
Blood is carried away from the heart by arteries. Blood that is rich in oxygen. Blood that is low in oxygen is returned to the heart by veins. there is more pressure in arteries than in veins.
Answer:
Electrons become excited.
Explanation:
Electrons in the chlorophyll get excited and pass on the energy to other electrons.
The answer is <span>the number of DNA mutations in an organism is measured over time to determine how long it will take for a new species to evolve.</span>
100% all offspring will be Ee - showing the dominant trait - detached earlobes
