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3 years ago

What are the solutions to the system of equations?

Mathematics

1 answer:

svet-max [94.6K]3 years ago

6 0

Answer:the third option is correct

Step-by-step explanation:

The system of equations are

y = 2x^2 - 5x - 7 - - - - - - - - - - -1

y = 2x + 2 - - - - - - - - - - - - - 2

We would equate equation 1 and equation 2. It becomes

2x^2 - 5x - 7 = 2x + 2

2x^2 - 5x - 2x - 7 - 2 = 0

2x^2 - 7x - 9 = 0

We would find two numbers such that their sum or difference is -7x and their product is - 18x^2. The two numbers are 2x and - 9x. Therefore

2x^2 + 2x - 9x - 9 = 0

2x(x + 1) - 9(x + 1) = 0

2x - 9 = 0 or x + 1 = 0

2x = 9 or x = - 1

x = 9/2 = 4.5

Substituting x = 4.5 or x = -1 into equation 2, it becomes

y = 2 × 4.5 + 2 or y = 2 × - 1 + 2

y = 11 or y = 0

Therefore, the solutions are

(4.5, 11) (- 1, 0)

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snow_lady [41]

Answer: $2i\sqrt{3}$

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Work Shown:

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Explanation:

The basic steps are to factor the radicand such that we pull out the -1 and we also pull out the largest perfect square factor. That way we can then apply the rule $\sqrt{A*B} = \sqrt{A}*\sqrt{B}$ to break up the root and simplify.

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Fudgin [204]

Answer:

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Step-by-step explanation:

step 1

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we know that

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where

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