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3 years ago

9

All the donated computers were shared equally by 5 classrooms. Which expression represents the number of computers each classroo

m received?

1 answer:

Sergio [31]3 years ago

4 0

X÷5. x is all of the donated computers and because it was equally shared between 5 classes you would ÷ by 5 to get the computer per class

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For which values of the variables the following equality is true?

Ilia_Sergeevich [38]

Answer:

For The value of a = 0 and c = 0 , The given expression equality is true

Step-by-step explanation:

Given expression as :

$\frac{3a^{2}+ac+2c-6a}{3a - c}$ = a - 2

Or, 3 a² + ac + 2 c - 6 a = ( a - 2 ) × ( 3 a - c )

Or, 3 a² + ac + 2 c - 6 a = 3 a² - ac - 6 a + 2 c

Or, ( 3 a² + ac + 2 c - 6 a ) - ( 3 a² - ac - 6 a + 2 c ) =0

Or, ( 3 a² - 3 a² ) + ( ac + ac ) + ( 2 c - 2 c ) + ( - 6 a + 6 a ) = 0

or, 0 + 2 ac + 0

Or, 2 ac = 0

∴ a =0 and c = 0

Hence For The value of a = 0 and c = 0 , The given expression equality is true . Answer

6 0

3 years ago

The length of a rectangle is increasing at a rate of 4 meters per day and the width is increasing at a rate of 1 meter per day.

puteri [66]

Answer:

$\displaystyle \frac{dA}{dt} = 102 \ m^2/day$

General Formulas and Concepts:

<u>Pre-Algebra</u>

Order of Operations: BPEMDAS

Brackets
Parenthesis
Exponents
Multiplication
Division
Addition
Subtraction

Left to Right<u> </u>

<u>Geometry</u>

Area of a Rectangle: A = lw

l is length
w is width

<u>Calculus</u>

Derivatives

Derivative Notation

Implicit Differentiation

Differentiation with respect to time

Derivative Rule [Product Rule]: $\displaystyle \frac{d}{dx} [f(x)g(x)]=f'(x)g(x) + g'(x)f(x)$

Step-by-step explanation:

<u>Step 1: Define</u>

<u /> $\displaystyle l = 10 \ meters$ <u />

<u /> $\displaystyle \frac{dl}{dt} = 4 \ m/day$ <u />

<u /> $\displaystyle w = 23 \ meters$ <u />

<u /> $\displaystyle \frac{dw}{dt} = 1 \ m/day$ <u />

<u />

<u>Step 2: Differentiate</u>

[Area of Rectangle] Product Rule: $\displaystyle \frac{dA}{dt} = l\frac{dw}{dt} + w\frac{dl}{dt}$

<u>Step 3: Solve</u>

[Rate] Substitute in variables [Derivative]: $\displaystyle \frac{dA}{dt} = (10 \ m)(1 \ m/day) + (23 \ m)(4 \ m/day)$
[Rate] Multiply: $\displaystyle \frac{dA}{dt} = 10 \ m^2/day + 92 \ m^2/day$
[Rate] Add: $\displaystyle \frac{dA}{dt} = 102 \ m^2/day$

Topic: AP Calculus AB/BC (Calculus I/II)

Unit: Implicit Differentiation

Book: College Calculus 10e

8 0

3 years ago

If AD=6 and AB=24, find AC

ruslelena [56]

When a perpendicular is dropped from the right-angle (C) to the opposite side AB, the metric relations apply:
BD*BA=a^2 ..........................(1)
AD*AB=b^2...........................(2)
BD*DA=DC^2........................(3)

Given AD=6, AB=24, using metric relation (2) above, we have
b^2=6*24=144
=>
b=sqrt(144)=12

By the way, we conclude that this is a 30-60-90 triangle because b/AB=(1/2)=sin(B) => B=30 degrees.

Answer: b=12

6 0

3 years ago

At a grocery store, the price of a watermelon is determined by how many pounds the watermelon weighs. The price of a watermelon

vodka [1.7K]

P = w * .6

Explanation: First, we must determine the price per pound of watermelon. To do this, we take the cost of the watermelons, and divide it by the number of pounds. 4.38 / 7.3, which is .6. This tells us each pound costs 60 cents, or $.6. We’re trying to say “The total price of watermelon would be the amount of watermelon bought times .6.” Plug in the variables you’re given, and you get p = w * 6.

7 0

4 years ago

Read 2 more answers

What is the equation of a line that contains point (2, -1) and is parallel to<br> y =<br> *x+3<br> ?

prohojiy [21]

Answer:

6 degrees

Step-by-step explanation:

8 0

3 years ago